A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°. what is the horizontal component of the
1 answer:
Answer:
The horizontal component of the velocity is approximately 13.22 m/s
Explanation:
The velocity of the kick which the football player gives the ball = 21 m/s
The angle of the path taken by the ball = 51°
The velocity can be represented vectorially, showing the vertical and horizontal components as follows;
v = 21 × cos(51°)· + 21 × sin(51°)·
Where we have;
The horizontal component of the velocity = 21 × cos(51°)
The vertical component of the velocity = 21 × sin(51°)
Therefore;
The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s
The horizontal component of the velocity ≈ 13.22 m/s.
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