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Juli2301 [7.4K]
2 years ago
14

Thor deja caer su martillo de la torre Torre Stark que tiene 95 pisos, si al llegar el Mjolnir al piso han transcurrido 9.5 segu

ndos. Determina: a) La velocidad con la que el Mjonir golpea el suelo
Physics
1 answer:
NARA [144]2 years ago
6 0

Answer:

La magnitud de la velocidad con la que Mjonir golpea el suelo es 93.2 m/s.

Explanation:

Podemos encontrar la velocidad con la que el martillo golpea el suelo usando la siguiente ecuación:

v_{f} = v_{0} - gt   (1)

En donde:

v_{f}: es la velocidad final =?

v_{0}: es la velocidad inicial = 0 (lo deja caer)

g: es la gravedad = 9.81 m/s²

t: es el tiempo = 9.5 s

Al reemplazar los valores anteriores en la ecuación (1), tenemos:

v_{f} = 0 - 9.81 m/s^{2}*9.5 s = -93.2 m/s                

El signo negativo se debe a que el vector velocidad está dirigido hacia abajo en el eje vertical (y).

Por lo tanto, la magnitud de la velocidad con la que Mjonir golpea el suelo es 93.2 m/s.

Espero que te sea de utilidad!

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A lab cart with a mass of 15 kg is moving with constant velocity, v, along a straight horizontal track. A student drops a 2 kg m
lbvjy [14]

The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

  • m₁: is the mass of the lab cart = 15 kg
  • m₂: is the <em>mass </em>of the object dropped = 2 kg
  • v_{1}_{i}: is the initial velocity of the<em> lab cart </em>
  • v_{2}_{i}: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
  • v_{1}_{f}: is the final velocity of the<em> lab cart </em>
  • v_{2}_{f}: is the <em>final velocity</em> of the <em>object </em>

Then, the horizontal momentum is:

15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/2400186?referrer=searchResults

I hope it helps you!            

4 0
2 years ago
It is estimated that uranium is relatively common in the earth's crust, occurring in amounts of 4 g / metric ton. A metric ton i
timama [110]

Answer:

The mass of Uranium present in a 1.2mg sample is 4.8 \cdot 10^{-6}\,mg

Explanation:

The ration between Uranium mass and total sample mass is: \frac{4g}{1000kg} =\frac{4g}{1000000g}=\frac{1}{250000}

For a sample of mass 1.2 mg, the amount of uranium is:

1.2\, mg \cdot \frac{1}{250000}=4.8 \cdot 10^{-6}\,mg

7 0
3 years ago
I NEED HELP ASAP!!!
Savatey [412]
I think option C is correct..hope it helps
3 0
2 years ago
Read 2 more answers
Help me please !!!!!
bezimeni [28]

Answer:

confounding cause they had exposure to many programmes

8 0
3 years ago
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A 20-N force acts on an object with a mass of 2.0kg. what is the objects acceleration?
ale4655 [162]

Answer:

10 m/s^2

Explanation:

Equation: F = ma.

a = acceleration

m = mass

F = force

Because we are trying to find acceleration instead of force we want to rearrange the equation to solve for a which is F/m = a.

F = 20

m = 2

a = ?

a = F/m

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a = 10 m/s^2

7 0
3 years ago
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