The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.
<h3>What is Electric field?</h3>
Electric field is the physical field that surrounds a charge. 
<h3>How to find final velocity of the electron when it moves some distance in a certain electric field?</h3>
- From Newton's second law, the acceleration the electron will be
 a=F/m=qE/m
- where q= charge of electron 
 E= electric field 
 m= mass of electron 
 =(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)
 =10¹⁵×0.526m/s²
- The kinematics equation v²=v0²+2a(Δx)
- where v=final velocity of the electron 
 v0=initial velocity of the electron =5×10⁶m/s
 a=acceleration of the electron =10¹⁵×0.526m/s²
 Δx=distance moved by the electron in east direction =1cm=10^-2m
- Now v^2=(5×10⁶)²+2×10¹⁵×0.526×10^-2
 =25×10¹²+10.52×10¹²
 =35.52×10¹²
- Now velocity of electron=5.95×10⁶m/s.
Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.
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