Answer:
v = 8.63 m/s
Explanation:
Neglecting the frictional forces, the law of conservation of energy can be applied to this situation as follows:
Potential Energy Gained By Athlete = Kinetic Energy Lost By Athlete
mgh = (0.5)mv²
gh = (0.5)v²
v = √2gh
where,
v = speed that the athlete must have when he plants the pole = ?
g = acceleration due to gravity = 9.8 m/s²
h = Height to be achieved by the athlete = 3.8 m
Therefore,
v = √(2)(9.8 m/s²)(3.8 m)
<u>v = 8.63 m/s</u>
Answer:
F = 5.83 10⁻¹⁷ N
Explanation:
The electric force is given by
F = k q₁ q₂ / r²
With Gauss's law electric field flow is equal to the charge inside the Gaussian surface, if we make a spherical surface around each drop, the force independent of small deformations due to air resistance
q₁ = q₂
F = 8.99 10⁹ (29 10⁻¹²)² / (0.36 10⁻²)²
F = 5.83 10⁻¹⁷ N
As the two drops have a charge of the same sign they repel