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Ipatiy [6.2K]
3 years ago
12

RETAKE - A push or a pull that causes an object to change its motion is called!

Physics
2 answers:
frozen [14]3 years ago
6 0

Answer: Force

Explanation: Force is defined as a push or pull acting on an object

Ann [662]3 years ago
6 0

Answer:

Force is defined as a push or pull acting on an object. Forces include gravity, friction, and applied force. Force causes changes in the speed or direction of motion. These changes are called acceleration.

Explanation:

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A car starts from the state of xestIf its velocity becomes 70 km/hr in 6 minutes, i) what is the accordine acceleration of F the
Alexxandr [17]

Answer: 3.5\ km

Explanation:

Given

Car starts from the state of rest and acquires a velocity of 70\ km/hr in 6 minutes

Final velocity in m/s is v=70\approx 19.44\ m/s

Using equation of motion

v=u+at\\\Rightarrow 19.44=0+a(6\times 60)\\\Rightarrow a=0.054\ m/s^2

Distance covered in 360 s

\Rightarrow v^2-u^2=2as\\\Rightarrow 19.44^2-0=2\times 0.054\times s\\\Rightarrow s=3500.64\ m\approx 3.5\ km

4 0
3 years ago
Dans un tube en U contenant du mercure ,on verse de l'autre côté de l'acide sulfurique de densité 1,84 et de l'autre côté de l'a
Iteru [2.4K]

Explanation:

Unclear question. The clear rendering reads;

"Into a U-tube containing mercury, pour on the other side sulfuric acid of density 1.84 and on the other side alcohol of density 0.8 so that the levels are in the same horizontal plane. The height of the acid above the mercury being 24 cm. What is the height of the bar and what variation of the level of the acid, when the mercury density is 13.6?

6 0
3 years ago
When the heart beats faster, blood vessels need to _____ more.<br> open <br> close move
Yuki888 [10]
I'm pretty sure it is open more
6 0
3 years ago
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the gravitational force between two objects is 1600 and what will be the gravitational force between the objects if the distance
Xelga [282]

I believe this is what you have to do:

The force between a mass M and a point mass m is represented by

F = G\frac{Mm}{r^{2} }

So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁

So F₁ = G(Mm/r^2)

Now the distance has doubled so lets account for this in F₂:

F₂ = G(Mm/(2r)^2)

Now square the 2 that gives you four and we can pull that out in front to give

F₂ = \frac{1}{4} G(Mm/r^2)

Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations

now we see that:

F₂ = \frac{1}{4} F₁

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6 0
3 years ago
Which is a valid velocity reading for an object?
pashok25 [27]

Answer:

45 m / s North is a valid vector reading for an object.

Explanation:

Then velocity will be defined by x km / hr North. And, magnitude of velocity defines the speed of the body. Although this tells the speed, but there is no description for the direction, so it's not a vector reading

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