Answer:
(a) ΔP=0.0245 kPa
(b) P=9.14 kPa
(c)ΔP=0.0245 kPa
Explanation:
(a) As it is perfect gas we can use
(P₁V₁)/T₁=(P₂V₂)/T₂
Since this constant volume so
P₁/T₁=P₂/T₂
T₂ is change in temperature
T₂=1.00+273.16
T₂=274.16 K

ΔP=6.71449-6.69
ΔP=0.0245 kPa
(b) As

(c) Same steps as in part (a)

ΔP=9.164-9.14
ΔP=0.0245kPa
Answer:
r2 = 2.401557 cm
distance = 0.10 cm
Explanation:
given data
radius = 2.50 cm
density = 15.0 nC/m
voltmeter read = 175
solution
we know here potential difference that is express as
ΔV =
...........1
so here
as here
is linear charge density
r2 = r1 ×
r2 = 2.40 ×
r2 = 2.401557 cm
and
here distance above surface will be
distance = r1 - r2
distance = 2.50 - 2.40
distance = 0.10 cm
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Answer:
The average surface temperature decreases the further you get from the Sun because the more distant planets receive less energy/heat/sunlight per square meter of their surface. This is because the energy from the Sun spreads out (becomes less concentrated) as you travel further from the source/Sun.
Explanation: