The angle of incidence for a ray of light passing through the center of curvature of a concave mirror is 0°.
The angle of incidence is the angle between the surface's normal and the incident ray. For a concave mirror, the normal of the surface is along the center of the curvature, and a ray of light passed through a center of curvature passes through the normal of the surface.
The ray of light retreats its path making a zero angle of reflection. The law of reflection state that the angle of incidence is equal to the angle of reflection; therefore, the angle of incidence of a concave surface passed through the center of curvature is zero degrees.
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Galaxy million of star and planet. gravitional wave field all the universe some planet explosive itself moving other places . Black holes Mass gravity field
Answer:
0.0196 j
Explanation:
i) The formula for kinetic energy is as follows: 0.5*m*v^2
ii) Since we have all the values all that's left is to plug them into the equation
iii) First, WE MUST, Convert grams into kgs as this is the SI unit of mass so 2.45/1000
iv) All that's left now is to plug it into the equation so:
0.5* (s.45/1000)*(4^2)
v) Lastly we add the unit joules at the end as we're talking about energy
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The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.
<h3>
Acceleration of the car </h3>
The acceleration of the car before stopping at the given distance is calculated as follows;
v² = u² + 2as
when the car stops, v = 0
0 = u² + 2as
0 = 15² + 2(76.5)a
0 = 225 + 153a
-a = 225/153
a = - 1.47 m/s²
<h3>Distance traveled when the speed is 32 m/s</h3>
If the same force is applied, then acceleration is constant.
v² = u² + 2as
0 = 32² + 2(-1.47)s
2.94s = 1024
s = 348.3 m
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Answer:
(a) The value of the ratio m₁/m₂ is 0.581
(b) the acceleration of the combined masses is 1.139 m/s²
Explanation:
Given;
The acceleration of force applied to M₁, a₁ = 3.10 m/s²
The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²
Let this force = F
According Newton's second law of motion;
F = ma
(a) the value of the ratio m₁/m₂
since the applied force is same in both cases, M₁a₁ = M₂a₂
(b) the acceleration of m₁ and m₂ combined as one object under the action force F
F = ma
Therefore, the acceleration of the combined masses is 1.139 m/s²
