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Ugo [173]
3 years ago
5

Which is true concerning the acceleration due to gravity? A. It decreases with increasing altitude. B. It is different for diffe

rent objects in free fall. C. It is a fundamental quantity. D. It is a universal constant. E. all of these
Physics
1 answer:
Kisachek [45]3 years ago
5 0

Answer:

The correct answer is  option 'a': It decreases with increase in altitude

Explanation:

Acceleration due to gravity is the acceleration that a  body is subjected to when it is freely dropped from a height from surface of any planet, ignoring the resistance that the object may face in it's motion such as drag due to any fluid.. The acceleration due to gravity is same for all the objects and is independent of their masses, it only depends on the mass of the planet and the radius of the planet on which the object is dropped. it's values varies with:

1) Depth from surface of planet.

2)Height from surface of planet.

3) Latitude of the object.

Hence it neither is a fundamental quantity nor an universal constant.

The variation of acceleration due to gravity with height can be mathematically written as:

g(h)=g_{surface}(1-\frac{2h}{R_{planet}})

where,

R is the radius of the planet

g_{surface} is value of acceleration due to gravity at surface.

hence we can see that upon increase in altitude the value of 'g' goes on decreasing.

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Answer:

Nitrogen and oxygen are by far the most common; dry air is composed of about 78% nitrogen (N2) and about 21% oxygen (O2). Argon, carbon dioxide (CO2), and many other gases are also present in much lower amounts; each makes up less than 1% of the atmosphere's mixture of gases.

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Aleks04 [339]

Explanation:

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7 0
2 years ago
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A man wishes to row the shortest possible distance from north to south across a river which is flowing at 2 km/hr from the east.
sweet-ann [11.9K]

From the diagram we have that

sin\theta = \frac{2}{4}

\theta = sin^{-1} (\frac{1}{2})

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8 0
3 years ago
Calculate the most charge that a 100pF capacitor (with a 1.0mm plate separation) can store if the capacitor breaks down with an
Misha Larkins [42]

Answer:

0.6 μC

Explanation:

C = capacitance of the capacitor = 100 x 10⁻¹² F

d = separation between the plates of capacitor = 1 mm = 1 x 10⁻³ m

E = Electric field = 6 x 10⁶ N/C

Q = Amount of charge

V = Potential difference

Potential difference is given as

V = E d

Amount of charge stored is given as

Q = CV

hence

Q = C E d

inserting the values

Q = (100 x 10⁻¹²) (6 x 10⁶) (1 x 10⁻³)

Q = 6 x 10⁻⁷ C

Q = 0.6 μC

5 0
2 years ago
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