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butalik [34]
2 years ago
15

Any entrée can be labeled "healthy" on a menu as long as it contains natural ingredients. True False

Chemistry
2 answers:
never [62]2 years ago
7 0
I'm pretty sure this statement is False.
bagirrra123 [75]2 years ago
3 0

Answer:

False.

Explanation:

Entrée is a culinary term used for a course during a meal service. In parts of the US and Canada, the word entrée is often used to refer to the main dish that is served while in other parts of the world, it usually means the starter or the simple meal that is served before the main dish / course. Entrées can be made of any component but the content of the natural ingredients does not define its healthy status. Thus, it is false to say that any entrée can be labelled "healthy" on a menu as long as it contains natural ingredients.

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What is the pH of a solution with a concentration of 2.4 × 10-5 molar H3O+? Show, or explain, the work used to solve this proble
MrRissso [65]
pH=-log|H_{3}O^{+}|\\\\
pH=-log2.4*10^{-5}=-(log2.4+log10^{-5})=-(0,38-5)=-(-4.62)\\\\
pH=4.62
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2 years ago
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What implications need to be considered when creating environmental policies?
Igoryamba

Answer:

How will it affect the environment? Is its benefit worth the cost?

Explanation:

when creating environmental policies you should always look into if it is worth it or not and how it will affect the environment  

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B. Determine the percent composition of each element in NaCl. (1 point) Must show work to
andrey2020 [161]

Answer:

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22.99+35.453=58.433.   22.99/58.433=   39%

Chlorine (Cl): (.5 point)

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6. The Earth’s electric field is directed vertically downward; at the ground level its strength is E = 130 N/C, and at an altitu
Alexxx [7]

Answer:

5.31x10⁻⁶ C

Explanation:

The cube is located 100 m altitude from the ground, so the superior face is at 100m and has E = 70 N/C, and the inferior face is at the ground with E = 130 N/C.

The electric field is perpendicular to the bottom and the top of the cube, so the total flux is the flux at the superior face plus the flux at the inferior face:

Фtotal = Ф100m + Фground

Where Ф = E*A*cos(α). α is the angle between the area vector and the field (180° at the topo and 0° at the bottom):

Фtotal = E100*A*cos(180°) + Eground*A*cos(0°)

Фtotal = 70A*(-1) + 130*A*1

Фtotal = 60A

By Gauss' Law, the flux is:

Фtotal = q/ε, where q is the charge, and ε is the permittivity constant in vacuum = 8.854x10⁻¹² C²/N.m²

A = 100mx100m = 10000 m²

q = 60*10000*8.854x10⁻¹²

q = 5.31x10⁻⁶ C

8 0
3 years ago
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