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2 years ago

if oxygen gas is collected over water at 23.5°c and 750.0 mm Hg, what is the pressure of the gas collected?

Chemistry

1 answer:

Alex73 [517]2 years ago

4 0

Answer:

Pressure of the Oxygen gas collected over water at 23.5°C = 728.35 mmHg = 0.958 atm

Explanation:

The gas collected over water will mix with water vapour.

The total pressure of the setup is then a sum of the partial pressure of the gas collected over the water and the vapour pressure of water at the temperature given.

Total Pressure = (Partial Pressure of Oxygen) + (Vapour Pressure of water at 23.5°C)

Total Pressure = 750 mmHg

Partial Pressure of Oxygen = ?

Vapour Pressure of water at 23.5°C = 21.6472 mmHg from literature

750 = (Partial Pressure of Oxygen) + 21.6472

Partial Pressure of Oxygen = 750 - 21.6472 = 728.3528 mmHg = 0.958 atm

Hope this Helps!!!

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The answer for the following problem is mentioned below.

Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule

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Given:

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