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mixas84 [53]
3 years ago
15

Is the magnitude of buoyant force same in all liquids????

Physics
1 answer:
valentina_108 [34]3 years ago
8 0

Answer:

No.  Buoyant force is equal to the weight of the displaced fluid.

B = mg

If ρ is the density of the fluid and V is the displaced volume:

B = ρVg

For fully submerged objects, where the displaced volume equals the volume of the object, buoyant force will be different in different fluids.

For floating objects, buoyant force equals the weight of the object, so it will be the same for any liquid that the object floats in.

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Are amplitude and wavelength related?<br> A: Yes<br> B: No
Trava [24]

The answer is A.Yes

Explanation:

The amplitude of a wave is the height of a wave as measured from the highest point of the wave to the lowest on the wave.

4 0
2 years ago
Which of the following is equal to the area under a velocity-time graph
Ksenya-84 [330]

-- The area under a velocity/time graph, between two points in time, is the difference in displacement during that period of time.

-- The area under a speed/time graph, between two points in time, is the distance covered during that period of time.

5 0
3 years ago
Read 2 more answers
A cricket starts at the 5 meter mark on a ruler. It jumps to the 10 meter mark. Then, it jumps back to the 6 meter mark. Calcula
belka [17]

We have that the cricket’s displacement is  

D_t=9meters

From the Question we are told that

Start position  5 meter mark

It jumps to the 10 meter mark.

it jumps back to the 6 meter mark.

Generally the equation for cricket’s displacement. is mathematically given as

D_t=Initial +final(displacement)\\\\D_t=(10-5)+(10-6)

D_t=9meters

For more information on this visit

brainly.com/question/24273210?referrer=searchResults

4 0
2 years ago
Describe the relationship between a moving object's mass and its kinetic energy.
Paladinen [302]

Answer:

E=\dfrac{1}{2}mv^2

Explanation:

If m is the mass of the object and v is the velocity of the object. The kinetic energy is due to the motion of an object. It is given by the relation as follows :

E=\dfrac{1}{2}mv^2

The above formula is used to find the kinetic energy of an object.

5 0
3 years ago
A person's center of mass is very near the hips, at the top of the legs. Model a person as a particle of mass mm at the top of a
muminat

Answer:

\mathbf{v_{max} = \sqrt{gL}}

Explanation:

Considering an object that moving about in a circular path,  the equation for such centripetal force can be computed as:

\mathbf {F = \dfrac{mv^2}{2}}

The model for the person can be seen in the diagram attached below.

So, along the horizontal axis, the net force that is exerted on the person is:

mg cos \theta = \dfrac{mv^2}{L}

Dividing both sides by "m"; we have :

g cos \theta = \dfrac{v^2}{L}

Making "v" the subject of the formula: we have:

v^2 = g Lcos \theta

v=\sqrt{ gL cos \theta

So, when \theta = 0; the velocity is maximum

∴

v_{max} = \sqrt{gL \ cos \theta}

v_{max} = \sqrt{gL \ cos (0)}

v_{max} = \sqrt{gL \times 1}

\mathbf{v_{max} = \sqrt{gL}}

Hence; the maximum walking speed for the person  is \mathbf{v_{max} = \sqrt{gL}}

3 0
3 years ago
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