Explanation:
There is no any direct relationship between the frequency of a sound relative the intensity of the sound.
Frequency is a perception of pitch of the sound whereas intensity determines the loudness of the sound. Intensity is proportional to amplitude of the sound.
So, it would be hard to determine how much more intense is a 6000 Hz tone than a 80 Hz tone.
I would say the smallest system for which the momentum will be preserved will be the ball plus the earth though in this case it would be the wooden floor since the last thing it does is bounce from the floor up in the air so that is the last system,
Answer:
yes there is a way to determine where to put the heavier weight on the other end.
Explanation:
For the beam to remain balanced the net torque on the beam must be zero, and this means the net torque on both sides must be the same.
torque = weight (force) x distance of the weight from the fulcrum
therefore
torque on the right side = torque on the left side
weight (force) on the left side x distance of the weight from the fulcrum =
weight (force) on the right side x distance of the weight from the fulcrum
therefore once we know the value of the two weights we want to put on the beam, and the distance of the less heavy weight from the fulcrum, we can substitute those values into the equation above to get the position we are to place the heavier weight to maintain balance.
Answer:
The second ball lands 1.5 s after the first ball.
Explanation:
Given;
initial velocity of the ball, u = 12 m/s
height of fall, h = 35 m
initial velocity of the second, v = 12 m/s
Time taken for the first ball to land;
determine the maximum height reached by the second ball;
v² = u² -2gh
at maximum height, the final velocity, v = 0
0 = 12² - (2 x 9.8)h
19.6h = 144
h = 144 / 19.6
h = 7.35 m
time to reach this height;
Total height above the ground to be traveled by the second ball is given as;
= 7.35 m + 35m
= 42.35 m
Time taken for the second ball to fall from this height;
total time spent in air by the second ball;
T = t₁ + t₂
T = 1.23 s + 2.94 s
T = 4.17 s
Time taken for the second ball to land after the first ball is given by;
t = 4.17 s - 2.67 s
T = 1.5 s
Therefore, the second ball lands 1.5 s after the first ball.