What must differ between the atom of two different element easy 10 POINTS

Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a

horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound Amount

Ni 12.7 g

CO 1.98 g

$Ni(CO)_4$ 0.597 g

Calculate the value of the equilibrium constant.

Answer: The value of equilibrium constant for the reaction is 2448.1

Explanation:

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of $Ni(CO)_4$ = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

$\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M$

$\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M$

$\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M$

For the given chemical reaction:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

The expression of equilibrium constant for the reaction:

$K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}$

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1$

Hence, the value of equilibrium constant for the reaction is 2448.1

4 0

4 years ago

I need help, lots of points to you, please give genuine answers, will mark brainliest.

PSYCHO15rus [73]

Answer:

this is hard

Explanation:

3 0

3 years ago

In the following reaction, identify the oxidized species, reduced species, oxidizing agent, and reducing agent. Be sure to answe

gtnhenbr [62]

Answer :

$Cl_2$ is reduced species.

$KI$ is oxidized species.

$Cl_2$ is oxidizing agent.

$KI$ is reducing agent.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

$Cl_2(aq)+2KI(aq)\rightarrow 2KCl(aq)+I_2(aq)$

The half oxidation-reduction reactions are:

Oxidation reaction : $2I^-\rightarrow I_2+2e^-$

Reduction reaction : $Cl_2^++2e^-\rightarrow 2Cl^-$

From this we conclude that the $'KI'$ is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and $'Cl_2'$ is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, $Cl_2$ is reduced species.

$KI$ is oxidized species.

$Cl_2$ is oxidizing agent.

$KI$ is reducing agent.

7 0

4 years ago

17.g to mL Density= 3.291g/mL

algol [13]

Density is defined as mass per unit volume
therefore density = mass ÷ volume

volume = mass÷density
volume in ml = 17 ÷ 3.291

4 0

3 years ago

please help timed !! due rn !! What happens to particle motion as two substances come to thermal equilibrium?

Gennadij [26K]

Answer:

When two substances that are of different temperatures are brought together and there is heat transfer such that the substances come to thermal equilibrium, the effect on the particle motion are as follows

1) The particle motion of the hotter body reduces, because its temperature reduces

2) The particle motion of the colder body increases, because its temperature increases

3) For gases, the volume and or pressure reduces for the hotter body, and if the temperature of the gas falls below the boiling point temperature, the gas will change into liquid

For the colder gas, only the volume and or pressure increases and the temperature rises

4) For liquids, if the temperature of the hotter liquid falls below the melting point, the hotter liquid will become a frozen solid

For the the colder liquid, if the temperature is raised above the boiling point, the liquid changes into gas and the temperature does not rise above the boiling point temperature, until all the cold liquid has evaporated

5) For solids, the vibration of the particles of the hotter substance reduces and the solid becomes more brittle

For the colder body, the rise in temperature causes an increase in vibration of the particles, and if the temperature rises above the melting point, the colder solid will begin to melt

Explanation:

7 0

3 years ago