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EastWind [94]
3 years ago
14

Can someone help me with my chemistry homework please???

Chemistry
1 answer:
taurus [48]3 years ago
4 0
<h2><u>Answers:</u></h2>

<u>1.) Lithium and Sulfide: </u>

  • Formula: \bold{Li_{2}S}
  • Ion Charges: \bold{Li~1+,~Li~1+,~S~2-}
<h3 />

<u>2.) Lithium and Chlorine:</u>

  • Formula: \bold{2LiCl}
  • Ion Charges: \bold{Li~1+, Li~1+,Cl~1-,Cl~1-}
<h3 />

<u>3.) Lithium and Oxygen: </u>

  • Formula: \bold{Li_{2}O}
  • Ion Charges: \bold{Li~1+,Li~1+,O~2-}

<u>4.) Lithium and Nitrogen:</u>

  • Formula: \bold{Li_{3}N}
  • Ion Charges: \bold{Li~1+,Li~1+,Li~1+,N~3-}

<u>5.) Magnesium and Sulfur:</u>

  • Formula: \bold{MgS}
  • Ion Charges: \bold{Mg~2+,S~2-}

<u>6.) Magnesium and Chlorine:</u>

  • Formula: \bold{MgCl_2}
  • Ion Charges: \bold{Mg~2+,Cl~1-,Cl~1-}

<u>7.) Magnesium and Oxygen:</u>

  • Formula: \bold{MgO}
  • Ion Charges: \bold{Mg~2+,O~2-}

<u>8.) Magnesium and Nitrogen: </u>

  • Formula: \bold{Mg_3N_2}
  • Ion Charges: \bold{Mg~2+,Mg~2+,Mg~2+,N~3-,N~3-}
<h2 /><h2><u>Explanation:</u></h2>

______________________________

<h3><u>Lithium and Sulfur: </u></h3>
  • In order to make Lithium Sulfide, There must be 2 Lithium and 1 Sulfur. You transfer the electrons from both Lithium's to the Sulfur.
<h3 /><h3><u>Lithium and Chlorine:</u></h3>
  • In order to make Lithium Chloride, There must be 2 Lithium and 2 Chlorine. You transfer the electrons from both Lithium's to the Chlorines, (One electron for each chlorine.)
<h3 /><h3><u>Lithium and Oxygen:</u></h3>
  • In order to make Lithium Oxide, There must be 2 Lithium and 1 Oxygen. You transfer the electrons from both Lithium to Oxygen.  
<h3 /><h3><u>Lithium and Nitrogen:</u></h3>
  • In order to make Lithium Nitride, There must be 3 Lithium and 1 Nitrogen. You transfer the electrons from all 3 Lithium to Nitrogen.  
<h3 /><h3><u>Magnesium and Sulfur:</u></h3>
  • In order to make Magnesium Sulfide, There must be 1 Magnesium and 1 Sulfur. You transfer the both electrons from Magnesium to Sulfur.
<h3 /><h3><u>Magnesium and Chlorine:</u></h3>
  • In order to make Magnesium Chloride, There must be 1 Magnesium and 2 Chlorine. You transfer on electron to each Chlorine.
<h3 /><h3><u>Magnesium and Oxygen:</u></h3>
  • In order to make Magnesium Oxide, There must be 1 Magnesium and 1 Oxygen. You transfer both electrons from Magnesium to Oxygen.
<h3 /><h3><u>Magnesium and Nitrogen:</u></h3>
  • In order to make Magnesium Nitride, There must be 3 Magnesium and 2 Nitrogen. You transfer 3 electrons from Magnesium to Nitrogen.
<h3 />

______________________________

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Classify each element. Note that another term for main group is representative, another term for semimetal is metalloid, and the
NikAS [45]

The question is incomplete, here is the complete question:

Classify each element. Note that another term for main group is representative, another term for semi-metal is metalloid, and the inner transition metals are also called the lanthanide and actinide series.

Hf, Am, In, Ta, As, Se, Rn

<u>Answer:</u>

Hafnium and tantalum are transition elements.

Americium is a inner transition element.

Indium, Selenium and Radon are main group elements.

Arsenic is a metalloid.

<u>Explanation:</u>

Main group elements are the elements which belong to s block and p block. They are also known as representative elements.

S-block elements are defined as the elements whose last electron enters s-sub shell. The general electronic configuration of these elements is ns^{1-2}

P-block elements are defined as the elements whose last electron enters p-sub shell. The general electronic configuration of these elements is np^{1-6}

Metalloids are defined as the elements which show intermediate properties between metals and non-metals. There are 7 metalloids in the periodic table. They are: Boron, Silicon, germanium, Arsenic, Antimony, Tellurium and Polonium.

Transition elements are known as d-block elements. D block elements are defined as the elements whose last electron enters d sub shell. The general electronic configuration of these elements is [(n-1)d^{1-10}ns^{0-2}]

Inner transition elements are known as (f block) elements. (F block) elements are defined as the elements whose last electron enters (f subshell). The general electronic configuration of these elements is [(n-2)f^{1-14}(n-1)d^{0-1}ns^{2}]. They are also known as lanthanide and actinide series.

For the given elements:

  • <u>Option 1:</u> Hf

Hafnium is the 72nd element of the periodic table having electronic configuration of [Xe]4f^{14}5d^26s^2

As, the last electron is entering the d subshell, it is a transition element.

  • <u>Option 2:</u> Am

Americium is the 95th element of the periodic table having electronic configuration of [Rn]5f^{7}6d^07s^2

As, the last electron is entering the (f subshell), it is a inner transition element.

  • <u>Option 3:</u> In

Indium is the 49th element of the periodic table having electronic configuration of [Kr]5s^25p^1

As, the last electron is entering the p subshell, it is a main group element.

  • <u>Option 4:</u> Ta

Tantalum is the 73rd element of the periodic table having electronic configuration of [Xe]4f^{14}5d^56s^2

As, the last electron is entering the d subshell, it is a transition element.

  • <u>Option 5:</u> As

Arsenic is the 33rd element of the periodic table having electronic configuration of [Ar]4s^24p^3

As, the last electron is entering the p subshell, it is a main group element. It shows an intermediate property of metal and non-metal. Thus, it is a metalloid.

  • <u>Option 6:</u> Se

Selenium is the 34th element of the periodic table having electronic configuration of [Ar]4s^24p^4

As, the last electron is entering the p subshell, it is a main group element.

  • <u>Option 7:</u> Rn

Radon is the 86th element of the periodic table having electronic configuration of [Xe]4f^{14}5d^{10}6s^26p^6

As, the last electron is entering the p subshell, it is a main group element.

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Answer: option C. HF

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What volume would 56.2 mL of gas at 820 mm of Hg occupy at 720 mm of Hg?
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Answer:

49.35  mL

Explanation:

Given: 56.2 mL of gas

To find: volume that 56.2 mL of gas at 820 mm of Hg would occupy at 720 mm of Hg

Solution:

At 820 mm of Hg, volume of gas is 56.2 mL

At 1 mm of Hg, volume of gas is \frac{56.2}{820}

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