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EastWind [94]
3 years ago
14

Can someone help me with my chemistry homework please???

Chemistry
1 answer:
taurus [48]3 years ago
4 0
<h2><u>Answers:</u></h2>

<u>1.) Lithium and Sulfide: </u>

  • Formula: \bold{Li_{2}S}
  • Ion Charges: \bold{Li~1+,~Li~1+,~S~2-}
<h3 />

<u>2.) Lithium and Chlorine:</u>

  • Formula: \bold{2LiCl}
  • Ion Charges: \bold{Li~1+, Li~1+,Cl~1-,Cl~1-}
<h3 />

<u>3.) Lithium and Oxygen: </u>

  • Formula: \bold{Li_{2}O}
  • Ion Charges: \bold{Li~1+,Li~1+,O~2-}

<u>4.) Lithium and Nitrogen:</u>

  • Formula: \bold{Li_{3}N}
  • Ion Charges: \bold{Li~1+,Li~1+,Li~1+,N~3-}

<u>5.) Magnesium and Sulfur:</u>

  • Formula: \bold{MgS}
  • Ion Charges: \bold{Mg~2+,S~2-}

<u>6.) Magnesium and Chlorine:</u>

  • Formula: \bold{MgCl_2}
  • Ion Charges: \bold{Mg~2+,Cl~1-,Cl~1-}

<u>7.) Magnesium and Oxygen:</u>

  • Formula: \bold{MgO}
  • Ion Charges: \bold{Mg~2+,O~2-}

<u>8.) Magnesium and Nitrogen: </u>

  • Formula: \bold{Mg_3N_2}
  • Ion Charges: \bold{Mg~2+,Mg~2+,Mg~2+,N~3-,N~3-}
<h2 /><h2><u>Explanation:</u></h2>

______________________________

<h3><u>Lithium and Sulfur: </u></h3>
  • In order to make Lithium Sulfide, There must be 2 Lithium and 1 Sulfur. You transfer the electrons from both Lithium's to the Sulfur.
<h3 /><h3><u>Lithium and Chlorine:</u></h3>
  • In order to make Lithium Chloride, There must be 2 Lithium and 2 Chlorine. You transfer the electrons from both Lithium's to the Chlorines, (One electron for each chlorine.)
<h3 /><h3><u>Lithium and Oxygen:</u></h3>
  • In order to make Lithium Oxide, There must be 2 Lithium and 1 Oxygen. You transfer the electrons from both Lithium to Oxygen.  
<h3 /><h3><u>Lithium and Nitrogen:</u></h3>
  • In order to make Lithium Nitride, There must be 3 Lithium and 1 Nitrogen. You transfer the electrons from all 3 Lithium to Nitrogen.  
<h3 /><h3><u>Magnesium and Sulfur:</u></h3>
  • In order to make Magnesium Sulfide, There must be 1 Magnesium and 1 Sulfur. You transfer the both electrons from Magnesium to Sulfur.
<h3 /><h3><u>Magnesium and Chlorine:</u></h3>
  • In order to make Magnesium Chloride, There must be 1 Magnesium and 2 Chlorine. You transfer on electron to each Chlorine.
<h3 /><h3><u>Magnesium and Oxygen:</u></h3>
  • In order to make Magnesium Oxide, There must be 1 Magnesium and 1 Oxygen. You transfer both electrons from Magnesium to Oxygen.
<h3 /><h3><u>Magnesium and Nitrogen:</u></h3>
  • In order to make Magnesium Nitride, There must be 3 Magnesium and 2 Nitrogen. You transfer 3 electrons from Magnesium to Nitrogen.
<h3 />

______________________________

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Consider the reaction: NO2(g) + CO(g) ⇌ NO(g) + CO2(g) Kc = 0.30 at some temperature. If the initial mixture has the concentrati
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This is an incomplete question, here is a complete question.

Consider the reaction: NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)

Kc = 0.30 at some temperature.

If the initial mixture has the concentrations below, the system is_______.

Chemicals   Concentration (mol/L)

- NO₂            0.024

- CO               0.360

- NO               0.180

- CO₂             0.120

Possible answers:

1) not at equilibrium and will remain in an unequilibrated state.

2) not at equilibrium and will shift to the left to achieve an equilibrium state.

3) not at equilibrium and will shift to the right to achieve an equilibrium state.

4) at equilibrium

Answer : The correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

Explanation:

Reaction quotient (Qc) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

First we have to determine the value of reaction quotient (Qc).

The given balanced chemical reaction is,

NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)

The expression for reaction quotient will be :

Q_c=\frac{[NO][CO_2]}{[NO_2][CO]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q_c=\frac{(0.180)\times (0.120)}{(0.024)\times (0.360)}=2.5

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K that means product = reactant. So, the reaction is in equilibrium.

The given equilibrium constant value is, K_c=0.30

From the above we conclude that, the Q>K that means reactant < product. So, the reaction is reactant favored that means reaction must shift to the reactant or left to be in equilibrium.

Hence, the correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

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