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Dmitriy789 [7]
3 years ago
13

How many moles of NaCl are in 75.0 g of NaCl ?

Chemistry
2 answers:
LenaWriter [7]3 years ago
6 0
Number of moles is found by formula n=mass/molar mass, or m/M. the molar mass is found by adding together the atomic masses of Na and Cl (22.99 + 35.45) to give 58.44 g/mol. Since the mass of NaCl is 75.0g, we find the number of moles as follows:
n = 75.0 / 58.44 = 1.28 mol
Mkey [24]3 years ago
6 0
To find the number of moles of any compound you should divide the mass over the molar mass of that compound 

<span>so for your question, </span>

<span>number of moles = mass/ molar mass </span>
<span>= 75.0 g / 58.443 g/mol </span>
<span>= 1.2833 </span>
<span>= 1.28 and note that the answer is rounded to 3 significant figures</span>
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<h3>Answer:</h3>

                The two possible compounds are;

                            1) Dimethyl Ether H₃C--O--CH₃

                           2) Ethanol  H₃C--CH₂--OH

<h3>Solution:</h3>

Step 1: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  =  52.14 ÷ 12.01

                      Moles of C  =  4.341 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  =  13.13 ÷ 1.01

                      Moles of H  =  13.00 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  =  34.73 ÷ 16.0

                      Moles of O  =  2.170 mol

Step 2: Find out mole ratio and simplify it;

                C                                        H                                     O

            4.341                                 13.00                              2.170

     4.341/2.170                      13.00/2.170                    2.170/2.170

               2                                      5.99                                    1

               2                                        6                                       1

Hence,  Empirical Formula  =  C₂H₆O

<h3>Result:</h3>

         As the molecular mass of compound is not given therefore, we can assume and guess the empirical formula to be the molecular formula. Hence, possible compounds are,

                            1) Dimethyl Ether H₃C--O--CH₃

                           2) Ethanol  H₃C--CH₂--OH

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