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beks73 [17]
3 years ago
11

If 1.27 moles of bromine gas (Br2) react with excess phosphorus (P), how many moles of phosphorus tribromide (PBr3) will be prod

uced?
Chemistry
1 answer:
frez [133]3 years ago
8 0

Answer:

0.85 mole of PBr3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3Br2 + 2P —> 2PBr3

From the balanced equation above,

3 moles of Br2 reacted to produce 2 moles of PBr3.

Therefore, 1.27 moles of Br2 will react to produce = (1.27 x 2)/ 3 = 0.85 mole of PBr3.

Therefore, 0.85 mole of PBr3 is produced by the reaction.

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state whether the following changes are physical or chemical for rancidipication fixation of water 2 tearing of paper 3 rusting
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The end of one bar magnet is placed near the end of another bar magnet. The two ends seem to push each other apart. Which of the
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A.The two ends are like poles

Explanation:

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The reason for this is that, when like poles of two magnets are made to face each other, the lines of forces are in opposite directions, hence the magnets repel.

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5 0
3 years ago
What factors affect the rate of a chemical reaction?
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Answer:

The answer to your question is below

Explanation:

Factors that affect the rate of a chemical reaction

- Temperature        If the temperature increases the rate of reaction increases.

- Concentration     The reaction will move where there less concentration it could be to the reactants of products.

- Particle size         The lower the particle size the higher the rate of reaction.

- Catalyst                 Catalyzers accelerate the rate of reaction

- Pressure                The reaction will move where there are fewer molecules.

3 0
3 years ago
Complete combustion of 8.10 g of a hydrocarbon produced 25.9 g of CO2 and 9.27 g of H2O. What is the empirical formula for the h
balu736 [363]

CxHy     +  O2    -->    x CO2     +    y/2  H2O

 

Find the moles of CO2 :     18.9g  /  44 g/mol   =    .430 mol CO2   = .430 mol of C in compound

Find the moles of H2O:      5.79g / 18 g/mol     =     .322 mol H2O   = .166 mol of H in compound

 

Find the mass of C and H in the compound:

                             .430mol  x 12  =  5.16 g C

                              .166mol  x 1g   = .166g H   

 

When you add these up they indicate a mass of 5.33 g for the compound, not 5.80g as you stated in the problem.

Therefore it is likely that either the mass of the CO2 or the mass of H20 produced is incorrect (most likely a typo).

In any event, to find the formula, you would take the moles of C and H and convert to a whole number ratio (this is usually done by dividing both of them by the smaller value).

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