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Softa [21]
3 years ago
3

Which is occurring when work is being done? energy is being reverted. energy is being decreased. energy is being increased. ener

gy is being transferred.?
Physics
2 answers:
Oxana [17]3 years ago
7 0
<h3>Answer;</h3>

Energy is being transferred

<h3><u>Explanation;</u></h3>
  • Work is the force applied over a given distance, in other words work is the product of force and distance.

Work = force × distance.

  • Work is measured in Joules.
  • Energy on the other hand, is the ability to do work.
  • According to the principle of work-energy a change in the kinetic energy is equivalent to the net work don e by the object. Therefore, when work is being done energy is being transferred from one point to another.
DENIUS [597]3 years ago
6 0

Energy is being transferred

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PLEASEEEE HEEEEELP!!!!!
8090 [49]

Answer:

Before:

p_{truck}=16400\ kg.m/s

p_{car}=10000\ kg.m/s

After:

p_{truck}=8000\ kg.m/s

p_{car}=8400\ kg.m/s

v_{fcar}=8.4\ m/s

F=9333.33 \ Nw

Explanation:

<u>Conservation of Momentum</u>

Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of

p_1=m_1v_{1o}+m_2v_{2o}

After the collision, they have speeds of v1f and v2f and the total momentum is

p_2=m_1v_{1f}+m_2v_{2f}

Impulse J is defined as

J=F.t

Where F is the average impact force and t is the time it lasted

Also, the impulse is equal to the change of momentum

J=\Delta p

As the total momentum is conserved:

p_1=p_2

m_1v_{1o}+m_2v_{2o}=m_1v_{1f}+m_2v_{2f}

We can compute the speed of the second object by solving the above equation for v2f

\displaystyle v_{2f}=\frac{ m_1v_{1o}+m_2v_{2o} -m_1v_{1f} }{  m_2 }

The given data is

m_1=2000\ kg

m_2=1000\ kg\\v_{1o}=8.2\ m/s\\v_{2o}=0\ m/s\\v_{1f}=4\ m/s

a) The impulse will be computed at the very end of the answer

b) Before the collision

p_{truck}=2000\cdot 8.2=16400\ kg.m/s

p_{car}=1000\cdot 0=0\ kg.m/s

c) After collision

p_{truck}=2000\cdot 4=8000\ kg.m/s

Compute the car's speed:

\displaystyle v_{2f}=\frac{ 16400+0 -8000 }{ 1000 }

v_{2f}=8.4\ m/s

And the car's momentum is

p_{car}=1000\cdot 8.4=8400\ kg.m/s

The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.

We can compute the impulse for each object

J_1=\Delta p_1=2000(4-8.2)=-8400 \N.s

The force can be computed as

\displaystyle F=\frac{J}{t}=-\frac{8400}{0.9}=-9333.33 \ Nw

The force on the car has the same magnitude and opposite sign

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4 years ago
What do any two samples of the element mercury (Hg) have in common?
Bas_tet [7]
A shiny surface,atomic number 80 and its <span>symbol  is </span>Hg<span> </span>
5 0
3 years ago
WILL GIVE YOU BRAINLIST IF YOU ANSWER
kvv77 [185]

Answer:

thanks

Explanation:

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5 0
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If a speed sound in air at o°c is 331m/s. what will be its value at 35 °c​
Lady_Fox [76]

Answer:

352 m/s

Explanation:

The velocity of sound in air is approximated as:

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v = 331 + 0.6 (35)

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How much time would it take to go up to the moon and back
marusya05 [52]

That completely depends on your speed and the trajectory (path) you choose.

The Apollo missions took about 3 days each way.

The New Horizons spacecraft passed the moon within a couple of hours after it was launched.

4 0
3 years ago
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