1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alchen [17]
3 years ago
8

A block of mass 1.3 kg is resting at the base of a frictionless ramp. A bullet of mass 50 g is traveling parallel to the ramp su

rface at 250 m/s. It collides with the block, enters it, and exits the other side at 100 m/s. How far up the ramp will the block travel?
Physics
1 answer:
aleksandrvk [35]3 years ago
3 0

Answer:

s = 2.65 m

Explanation:

given,

mass of block,M = 1.3 Kg

mass of bullet,m = 50 g = 0.05 Kg

speed of bullet,u  = 250 m/s

speed of bullet after collision,v = 100 m/s

distance traveled by the block = ?

Assuming the angle of inclination of ramp equal to 40°

calculating the speed of the block

using conservation of momentum

M u' + m u = m v + M v'

initial speed of the block is equal to zero

0 + 0.05 Kg x 250 = 0.05 x 100 + 1.3 x v'

1.3 v' = 7.5

  v' = 5.77 m/s

now, calculation of acceleration

equation  the horizontal component

-mg sin θ = ma

  a = - g sin θ

  a = - 9.8 x sin 40°  

  a = -6.29 m/s²

using equation of motion for the calculation of distance moved by the block

v² = u² + 2 a s

0² = 5.77² + 2 x (-6.29) x s

12.58 s = 33.29

s = 2.65 m

hence, the distance moved by the block is equal to 2.65 m

You might be interested in
A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.550 and
devlian [24]

To solve this exercise it is necessary to apply the concepts related to the Snells law.

The law defines that,

n_1 sin\theta_1 = n_2 sin\theta_2

n_1 = Incident index

n_2 = Refracted index

\theta_1 = Incident angle

\theta_2 = Refracted angle

Our values are given by

n_1 = 1.550

n_2 = 1.361

\theta_2 =90\° \rightarrowRefractory angle generated when light passes through the fiber.

Replacing we have,

(1.55)sin \theta_1 = (1.361) sin90

sin \theta_1 = \frac{(1.361) sin90}{(1.55)}

\theta_1 =sin^{-1} \frac{(1.361) sin90}{(1.55)}

\theta_1 =61.4\°

Now for the calculation of the maximum angle we will subtract the minimum value previously found at the angle of 90 degrees which is the maximum. Then,

\theta_{max} = 90-\theta \\\theta_{max} =90-61.4\\\theta_{max}=28.6\°

Therefore the critical angle for the light ray to remain insider the fiber is 28.6°

6 0
3 years ago
An object with a mass of 1500kg accelerates 10.0m/s when unknown force is applied to it. What is the amount of force?
Hatshy [7]

Answer:

<h3>The answer is 15000 N</h3>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1500 × 10

We have the final answer as

<h3>15,000 N</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
(quick help please??)A mechanic uses a mechanical lift to raise a car. The car weighs 10,200 N. The work required to do this was
GuDViN [60]
I believe It would be 2.2m
5 0
3 years ago
What is the increase in pressure required to decrease volume of mercury by 0.001%
REY [17]

Answer:

Explanation:

Using Boyles law

Boyle's law states that, the volume of a given gas is inversely proportional to it's pressure, provided that temperature is constant

V ∝ 1 / P

V = k / P

VP = k

Then,

V_1 • P_1 = V_2 • P_2

So, if we want an increase in pressure that will decrease volume of mercury by 0.001%

Then, let initial volume be V_1 = V

New volume is V_2 = 0.001% of V

V_2 = 0.00001•V

Let initial pressure be P_1 = P

So,

Using the equation above

V_1•P_1 = V_2•P_2

V × P = 0.00001•V × P_2

Make P_2 subject of formula by dividing be 0.00001•V

P_2 = V × P / 0.00001 × V

Then,

P_2 = 100000 P

So, the new pressure has to be 10^5 times of the old pressure

Now, using bulk modulus

Bulk modulus of mercury=2.8x10¹⁰N/m²

bulk modulus = P/(-∆V/V)

-∆V = 0.001% of V

-∆V = 0.00001•V

-∆V = 10^-5•V

-∆V/V = 10^-5

Them,

Bulk modulus = P / (-∆V/V)

2.8 × 10^10 = P / 10^-5

P = 2.8 × 10^10 × 10^-5

P = 2.8 × 10^5 N/m²

3 0
3 years ago
The horse on a carousel is 3.5m from the central axis.A. If the carousel rotates at 0.13 rev/s , how long does it take the horse
Kitty [74]

Answer:

a. 15.4 seconds

b. 0.455 m/s

Explanation:

a. The carousel rotates at 0.13 rev/s.

This means that it takes the carousel 1 sec to make 0.13 of an entire revolution.

This means that time it will take to make a complete revolution is:

1 / 0.13 = 7.7 seconds

Therefore, the time it will take to make 2 revolutions is:

2 * 7.7 = 15.4 seconds

b. Let us calculate the linear velocity. Angular velocity is given as:

\omega = v / r

where v = linear velocity and r = radius

The radius of the circle is 3.5 m and the angular velocity is 0.13 rev/s, therefore:

0.13 = v / 3.5

v = 3.5 * 0.13 = 0.455 m/s

Linear velocity is 0.455 m/s

8 0
3 years ago
Other questions:
  • A stone is dropped from rest from the top of a cliff into a pond below. If its initial height is 10 m, what is its speed when it
    15·1 answer
  • Which of these shows magnesium and oxygen immediately before they join to form an ionic substance?
    12·2 answers
  • What is the magnitude of the electric field at a distance 60 cm from the center of the sphere? The radius of the sphere 30 cm, t
    10·2 answers
  • An internal combustion engine has an efficiency of 22.3%. This engine is used to deliver 6.25x 40 J of work to drive the motion
    5·1 answer
  • When an object has a net force of zero, then it is said to be in what?
    14·1 answer
  • Please help me with physics a very nice person
    10·1 answer
  • PLEASE HLEP ME ASAP
    15·1 answer
  • A metal ring 5.00 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpend
    7·1 answer
  • How to solve period per loop
    14·1 answer
  • What is the main limitation of debye huckel theory​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!