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3 years ago

I have got a project about hacks so i need help

Physics

2 answers:

zhannawk [14.2K]3 years ago

5 0

Hacks in real life are tricks to help solve a problem with a simple solution.

Say for example, add a pinch of salt to whip egg white faster.

inessss [21]3 years ago

3 0

Answer:

you mean life hack ?...

Explanation:

well life hack is a strategy adopted in order to manage one's time and daily activities in a more efficient way.

life hacks are intended to improve your life e.g setting an alarm clock in order to wake up on time or putting a stoking over the end of your vacuum cleaner to help you find a tiny item etc.

Hope this helps

You might be interested in

If you push on the wall with a force of 400 N, what is the magnitude of the force at the wall exerts on you?

Inessa05 [86]

Answer:

400 N

Explanation:

Due to action-Reaction, the wall pushes back on the person with a force of equal magnitude and in opposite direction to the force exerted by the person.

So the magnitude must be also 400 N.

7 0

3 years ago

Using a mass of 1. 8 g and the volume displaced by the sample, calculate the sample's density. Question 17 options: 0. 17 g/mL 0

LUCKY_DIMON [66]

The sample's density with respect to the volume it displaces is equal to: C. 0. 60 g/mL

Given the following data:

Mass = 1.8 grams

Initial volume = 20 mL

Final volume = 23 mL

To calculate the sample's density:

First of all, we would determine the volume displaced by the sample;

$Volume \;displaced = 23-20$

Volume displaced = 3 mL

Density can be defined as mass all over the volume of an object. Thus, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

$Density = \frac{Mass}{Volume}$

Substituting the given parameters into the formula, we have;

$Density = \frac{1.8}{3}$

Density = 0.60 g/mL

8 0

3 years ago

A Semi truck(m=20,000kg) is 10 m from a car(m=200kg). What is the force of gravity between them(G=6.67*10^-11N•m^2/kg^2)

gregori [183]

Answer:

F = 2.668*10_-6[N]

Explanation:

We can calculate this force using the law of universal gravitation raised by Isaac Newton

$m_{t}=20000[kg]\\m_{c}= 200[kg]\\r = 10[m]\\G = 6.67*10^{-11}[\frac{N*m^{2} }{kg} ] \\$

And the force is given by the following expression:

$F=G*\frac{m_{t}*m_{c}}{r^{2} } \\F=6.67*10^{-11} *\frac{20000*200}{10^{2} }\\F=2.668*10^{-6} [N]$

5 0

3 years ago

A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. (a) A

mariarad [96]

Answer:

The question is not complete. see the complete question in the explanation section. The correct option is highlighted in bold

Explanation:

(a)A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. At the moment contact is made with the battery, the voltage across the resistor is

I. greater than the battery's terminal voltage.

II. equal to the battery's terminal voltage.

III. less than the battery's terminal voltage, but greater than zero.

IV. zero.

Option (i) is not correct as the voltage across the resistor cannot be greater than the terminal voltage since the current is yet to flow through the resistor. Option (ii) is correct as both the resistor voltage and the terminal voltage will just equal at the instance of connection. Option (ii) can only be possible after the current must have passed through the resistor for a while not immediately after contact. Option (iv) is not correct, as this can only be possible is the contact is open.

(b)A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. At the moment contact is made with the battery the voltage across the capacitor is

I. greater than the battery's terminal voltage.

II. equal to the battery's terminal voltage.

III. less than the battery's terminal voltage, but greater than zero.

IV. zero.

Option (i) is not correct as the capacitor is yet to charge talk less of the its voltage exceeding that of the battery. Option (ii) can only be correct if the capacitor is fully charged not when it has just been connected. Option (iii) can only occur if the capacitor is discharging. Option (iv) is the correct answer as the capacitor is about to start charging

8 0

4 years ago

Daring Darless wishes to cross the Grand Canyon of the Snake River by being shot from a cannon. She wishes to be launched at 56°

Roman55 [17]

Answer:

She must be launched with a speed of 74.2 m/s.

Explanation:

Hi there!

The equations of the horizontal component of the position vector and the vertical component of the velocity vector are the following:

x = v0 · t · cos θ

vy = v0 · sin θ + g · t

x = horizontal distance traveled at time t.

v0 = initial velocity.

t = time.

θ = launching angle.

vy = vertical component of the velocity vector at time t.

g = acceleration due to gravity (-9.8 m/s²).

To just cross the 520-m gap, the maximum height of the flight must be reached halfway of the gap at 260 m horizontally (see attached figure).

When she is at the maximum height, her vertical velocity is zero. So, when x = 260 m, vy = 0. Using both equations we can solve the system for v0:

x = v0 · t · cos θ

Solving for v0:

v0 = x/ (t · cos θ)

Replacing v0 in the second equation:

vy = v0 · sin θ + g · t

0 = x/(t·cos(56°)) · sin(56°) + g · t

0 = 260 m · tan (56°) / t - 9.8 m/s² · t

9.8 m/s² · t = 260 m · tan (56°) / t

t² = 260 m · tan (56°) / 9.8 m/s²

t = 6.27 s

Now, let's calculate v0:

v0 = x/ (t · cos θ)

v0 = 260 m / (6.27 s · cos(56°))

v0 = 74.2 m/s

She must be launched with a speed of 74.2 m/s.

5 0

3 years ago