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melisa1 [442]
3 years ago
8

A nuclear explosion may release tremendous amounts of energy in the form of noise, heat, visible light, radiation and an atmosph

eric shock wave. An observer watching the explosion from the vacuum of nearby space would be able to experience which of these types of energy?
Physics
1 answer:
Nina [5.8K]3 years ago
8 0
Think about how each of noise, heat, visible light, radiation and atmospheric shock waves travel. Which ones require air particles to travel?

A vacuum has no air particles within it, it is completely empty.

Therefore, any of the above that requiring particles to travel will not be able to cross it and the observer will not experience it.
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True or False: A chemical reaction always happens when two substances are combined. (please help fast this is a test)
Makovka662 [10]

Answer:

no not always sometimes they react at all so false I hope I helped :)

6 0
3 years ago
Read 2 more answers
A long, East-West-oriented power cable carrying an
Alla [95]

Answer:

200A

Explanation:

Given that

the distance between earth surface and power cable d = 8m

when the current is flowing through cable , the magnitude flux density at the surface is 15μT

when the current flow throught is zero the magnitude flux density at the surface is 20μT

The change in flux density due to the current flowing in the power cable is

B = 20μT - 15μT

B =5μT -----(1)

The expression of magnitude flux density produced by the current carrying cable is

B=\frac{\mu_0I}{2\pi d}-----(2)

Substitute the value of flux density

B from eqn 1 and eqn 2

\frac{\mu_0I}{2\pi d}=5\times 10^-^6\\\\\frac{(4\pi \times 10^-^7)I}{2 \pi (8)} =5\times 10^-^6\\\\I=200A

Therefore, the magnitude of current I is 200A

8 0
3 years ago
Is energy matter? Is gravity matter? Why or why not
Alja [10]

No, because the energy is the capacity for performing work. Gravity is the force that draws everything to the earth's center.

5 0
3 years ago
Assume the following values: d1 = 0.880 m , d2 = 1.11 m , d3 = 0.560 m , d4 = 2.08 m , F1 = 510 N , F2 = 306 N , F3 = 501 N , F4
dsp73

Answer:

= 2630.6 N.m

Explanation:

(FR)x = ΣFx = -F4 = -407 N

(FR)y = ΣFy =-F1-F2 -F3 = -510 - 306 - 501 = -1317 N

(MR)B =ΣM + Σ(±Fd)

= MA + F1(d1 +d2) + F2d2 - F4d3

= 1504 + 510(0.880+1.11) +306(1.11) - 407(0.560)

= 2630.64 N.m (counterclockwise)

6 0
3 years ago
A ball is thrown horizontally from a window that is 15.4 meters high at a speed of 3.01 m/s. How far will the ball go before hit
tia_tia [17]

The distance travelled by the ball that is thrown horizontally from a window that is 15.4 meters high at a speed of 3.01 m/s is 5.34 m

s = ut + 1 / 2 at²

s = Distance

u = Initial velocity

t = Time

a = Acceleration

Vertically,

s = 15.4 m

u = 0

a = 9.8 m / s²

15.4 = 0 + ( 1 / 2 * 9.8 * t² )

t² = 3.14

t = 1.77 s

Horizontally,

u = 3.01 m / s

a = 0 ( Since there is no external force )

s = ( 3.01 * 1.77 ) + 0

s = 5.34 m

Therefore, the distance travelled by the ball before hitting the ground is 5.34 m

To know more about distance travelled

brainly.com/question/12696792

#SPJ1

7 0
1 year ago
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