A nuclear explosion may release tremendous amounts of energy in the form of noise, heat, visible light, radiation and an atmosph
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Answer:
a = 12.8 m/s^2
Explanation:
To find the centripetal acceleration you use the following formula:
(1)
v: tangential speed of the rock = 17.90mph
r: radius of the orbit = 1000cm/2 = 500cm = 0.5m
You first change the units of the tangential velocity in order to replace the values of v and r in the equation (1):
Then, you use the equation (1):
hence, the centripetal acceleration is 12.8 m/s^2
Answer:
Part a)
Part b)
Explanation:
Part A)
As we know that time period of the motion is given as
so we have
now at the point of maximum amplitude the force equation when Normal force is about to zero is given as
so we have
Part b)
Now if the amplitude of the SHM is 6.23 cm
and now at this amplitude if object will lose the contact then in that case again we have
so now we have