Answer : The standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The combustion of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
Now we are reversing reaction 1 and then adding both the equations, we get :
(1) 
(2)
The expression for enthalpy change for the reaction will be,
Therefore, the standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol
Answer:
Explanation:
Nitrogen has a lone pair of electrons. That would mean that NH3 is minus at the left end in this case.
H
:N H
H
Methane has its Hs 90 degrees (approximately apart.
H
H C H
H
The pulling forces on the methane cancel each other out. When that happens the chemical is non polar.
Mechanical waves can help in the treatment of cancer due to heat generated by the high frequency waves.
<h3>What is mechanical wave?</h3>
A mechanical wave is a wave that requires material medium for its propagation, example include;
- water waves,
- sound waves, and
- seismic waves.
<h3> Mechanical waves in treatment of cancers</h3>
Sound wave in example of mechanical wave because it requires material medium for its propagation.
High-frequency sound waves (HIFU) is used in the treatment of cancer because the strong beam generates heat which is directed to a specific part of a cancer.
The heat generated destroys the cancer cells.
Thus, mechanical waves can help in the treatment of cancer due to heat generated by the high frequency waves.
Learn more about mechanical waves here: brainly.com/question/9242091
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Answer:
8.37 grams
Explanation:
The balanced chemical equation is:
C₆H₁₂O₆ ⇒ 2 C₂H₅OH (l) + 2 CO₂ (g)
Now we are asked to calculate the mass of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.
From the ideal gas law we can determine the number of moles that the 2.25 L represent.
From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.
PV = nRT ⇒ n = PV/RT
n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂
Moles glucose required:
0.093 mol CO₂ x ( 1 mol C₆H₁₂O₆ / 2 mol CO₂ ) = 0.046 mol C₆H₁₂O₆
The molar mass of glucose is 180.16 g/mol, then the mass required is
0.046 mol x 180.16 g/mol = 8.37 g
The spaceship does not have any gravitational pull. A spaceship can not produce its own gravity like Earth does.
