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dexar [7]
3 years ago
14

un estudiante introduce un corcho cuya densidad es 0.95 g/cm en cada uno de los liquidos que figura representa mejor la situacio

n
Chemistry
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer:

La respuesta correcta es la opción A.

Explicación:

La densidad del corcho es 0.95g / cm3 por lo que se hundirá en la solución de acetona porque el corcho es más denso que la solución de acetona mientras que por otro lado, el corcho flotará en otros dos líquidos porque la densidad del corcho es menor que en otros dos líquidos o, en otras palabras, los dos líquidos son más densos que el corcho, por eso el corcho flotará en estos dos líquidos.

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How many ml of co2 would be produced at 745 torr and 28°C
Marizza181 [45]

Answer:

Se aplica la leyes d ellos gases ideales para esto se convierten las unidades de Presión en atmósferas y Temperatura a Kelvin y si no se tiene el volumen el volumen equivale a 22.4Litros

Explanation:

3 0
3 years ago
State with reasons, whether sulphur dioxide is acting as an oxidizing agent or a reducing agent in each of the following reactio
evablogger [386]

Answer:

A) oxidizing agent is SO2

B) NaClO is the oxidizing agent

Explanation:

A) This is a redox reaction in which oxidation and reduction occur simultaneously.

Thus, in 2H2S(g) + SO2(g) -> 2H2O(l) + 3S(s);

H2S is reduced as follows;

H2S → S + 2H+ + 2e−

We can see that SO2 has been reduced while H2S gets oxidized since it has changed state from - 2 to 0 . Thus sulphur dioxide is the oxidizing agent.

B) SO2(g) + H2O(l) + NaClO(aq) -> NaCl(aq) + H2SO4(aq)

In this, SO2 undergoes oxidation and NaClO is the oxidizing agent

4 0
3 years ago
The ________________and ______________ of magma cause igneous rocks to form.
LekaFEV [45]

Answer:

The solidifying/cooling and crystallizing of magma causes igneous rocks to form.

6 0
3 years ago
what is the concentration of hydroxide ions after 50.0 ml of 0.250 m naoh is added to 120 ml of 0.200 m na2so4? please show all
Galina-37 [17]

The concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

What is meant by concentration?

Concentration is the total amount of solute present in the given volume of solution. this is expressed in terms of molarity, molality, mole fraction, normality etc. The term concentration mostly refers to the solvents and solutes present in the solution.

Concentration of hydroxide ions can be calculated by,

M (OH^-) = V (NaOH) x M (NaOH) / V (total) = 50ml x 0.250M / 50ml + 120ml = 0.0735M = 7.35 x 10^-2 M.

where M (OH^-) = concentration of hydroxide ions, V(NaOH) = volume of NaOH, M(NaOH) = concentration of NaOH.

Therefore, the concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

To learn more about concentration click on the given link brainly.com/question/17206790

#SPJ4

5 0
1 year ago
When a substance was dissolved in water, the temperature of the water increased. This process is described as
NemiM [27]
The correct answer will be A
3 0
3 years ago
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