Explain using physics vocabulary WHY the volume increases as the temperature increases.

Physics

1 answer:

Sveta_85 [38]2 years ago

4 0

Answer:

P V = n R T ideal gas equation

V = k T where k = a constant and equals k = n R / P

V is proportional to T when other factors are constant

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What is one way to take advantage of creating even more kinetic energy on this particular technologically advanced field

ch4aika [34]

Incomplete question. However, I provided a brief about Kinetic energy generation.

Explanation:

Interestingly, Kinetic energy in simple terms refers to the energy possessed by a body in motion.

It is often calculated using the formula E = $\frac{1}{2}MV^{2}$

A good example of creating even more kinetic energy is a hand crank toy car that moves after you wind it a little, when the car moves it is generating another measure of K.E.

7 0

2 years ago

the two forces f1 and f2 acting at A have a resultant force of Fr= -100lb. determine the magnitude and coordinate direction angl

faust18 [17]

Two forces F1 and F2 act on the screw eye. The resultant force FR has a magnitude of 125 lb and the coordinate direction angles shown in (Figure 1) . Determine the magnitude of F2. Determine the coordinate direction angle α2 of F2. Determine the coordinate direction angle β2 of F2. Determine the coordinate direction angle γ2 of F2.

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3 years ago

Long Jump: inital center of mass height of 1.08 m, final center of mass height of 0.42 m, projection velocity of 8.7 m/s, projec

sammy [17]

Answer:

1) The maximum jump height is reached at A. $0.337s$

2) The maximum center of mass height off of the ground is B. $1.64m$

3) The time of flight is C. $0.834s$

4) The distance of jump is B. $7.49m$

Explanation:

First of all we need to decompose velocity in its rectangular components, so

$v_{xi}=8.7m/s(cos 22.3\°)=8.05m/s= constant\\v_{yi}=8.7m/s(sin 22.3\°)=3.3m/s$

1) We use, $v_{fy}=v_{iy}-gt$ , as we clear it for $t$ and using the fact that $v_{fy}=0$ at max height, we obtain $t=\frac{v_{iy}}{g} =\frac{3.3m/s}{9,8m/s^{2}} =0.337s$

2) We can use the formula $y_{max}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}$ for $t=0.337s$ , so

$y_{max}=1.08m+(3.3m/s)(0.337s)-\frac{(9.8m/s^{2})(0.337)^{2}}{2}=1.64m$

3) We can use the formula $y_{f}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}$ , to find total time of fligth, so $0.42=1.08+3.3t-\frac{(9.8)t^{2}}{2}\\0=-4.9t^{2}+3.3t+0.66$ , as it is a second-grade polynomial, we find that its positive root is $t=0.834s$