Answer:
19.08 m/s
Explanation:
f = actual frequency emitted by the parked car's horn = 440 Hz
V = speed of sound = 342 m/s
f' = frequency of the horn observed by you = 466 Hz
v = speed of your car moving towards the parked car = ?
frequency of the horn observed by you is given as
![f' = \frac{Vf}{V - v}](https://tex.z-dn.net/?f=f%27%20%3D%20%5Cfrac%7BVf%7D%7BV%20-%20v%7D)
![466 = \frac{(342)(440)}{342 - v}](https://tex.z-dn.net/?f=466%20%3D%20%5Cfrac%7B%28342%29%28440%29%7D%7B342%20-%20v%7D)
v = 19.08 m/s
Answer: 2. Solution A attains a higher temperature.
Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.
In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.
Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.
<em>We have a formula for such condition,</em>
.....................................(1)
where:
= temperature difference
- c= specific heat of the body
<u>Proving mathematically:</u>
<em>According to the given conditions</em>
- we have equal masses of two solutions A & B, i.e.
![m_A=m_B](https://tex.z-dn.net/?f=m_A%3Dm_B)
- equal heat is supplied to both the solutions, i.e.
![Q_A=Q_B](https://tex.z-dn.net/?f=Q_A%3DQ_B)
- specific heat of solution A,
![c_{A}=2.0 J.g^{-1} .\degree C^{-1}](https://tex.z-dn.net/?f=c_%7BA%7D%3D2.0%20J.g%5E%7B-1%7D%20.%5Cdegree%20C%5E%7B-1%7D)
- specific heat of solution B,
![c_{B}=3.8 J.g^{-1} .\degree C^{-1}](https://tex.z-dn.net/?f=c_%7BB%7D%3D3.8%20J.g%5E%7B-1%7D%20.%5Cdegree%20C%5E%7B-1%7D)
&
are the change in temperatures of the respective solutions.
Now, putting the above values
![Q_A=Q_B](https://tex.z-dn.net/?f=Q_A%3DQ_B)
![m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1](https://tex.z-dn.net/?f=m_A.c_A.%20%5CDelta%20T_A%3Dm_B.c_B%20.%20%5CDelta%20T_B%5C%5C%5C%5C2.0%5Ctimes%20%5CDelta%20T_A%3D3.8%20%5Ctimes%20%5CDelta%20T_B%5C%5C%5C%5C%20%5CDelta%20T_A%3D%5Cfrac%7B3.8%7D%7B2.0%7D%5Ctimes%20%5CDelta%20T_B%5C%5C%5C%5C%5C%5C%5Cfrac%7B%5CDelta%20T_%7BA%7D%7D%7B%5CDelta%20T_%7BB%7D%7D%20%3D%20%5Cfrac%7B3.8%7D%7B2.0%7D%3E1)
Which proves that solution A attains a higher temperature than solution B.
Answer:
D. demand; increased
Explanation:
Demand is how much people want it.
Answer:
<h2><em>
12.45eV</em></h2>
Explanation:
Before calculating the work function, we must know the formula for calculating the kinetic energy of an electron. The kinetic energy of an electron is the taken as the difference between incident photon energy and work function of a metal.
Mathematically, KE = hf - Ф where;
h is the Planck constant
f is the frequency = c/λ
c is the speed of light
λ is the wavelength
Ф is the work function
The formula will become KE = hc/λ - Ф. Making the work function the subject of the formula we have;
Ф = hc/λ - KE
Ф = hc/λ - 1/2mv²
Given parameters
c = 3*10⁸m/s
λ = 97*10⁻⁹m
velocity of the electron v = 3.48*10⁵m/s
h = 6.62607015 × 10⁻³⁴
m is the mass of the electron = 9.10938356 × 10⁻³¹kg
Substituting the given parameters into the formula Ф = hc/λ - 1/2mv²
Ф = 6.63 × 10⁻³⁴*3*10⁸/97*10⁻⁹ - 1/2*9.11*10⁻³¹(3.48*10⁵)²
Ф = 0.205*10⁻¹⁷ - 4.555*10⁻³¹*12.1104*10¹⁰
Ф = 0.205*10⁻¹⁷ - 55.163*10⁻²¹
Ф = 0.205*10⁻¹⁷ - 0.0055.163*10⁻¹⁷
Ф = 0.1995*10⁻¹⁷Joules
Since 1eV = 1.60218*10⁻¹⁹J
x = 0.1995*10⁻¹⁷Joules
cross multiply
x = 0.1995*10⁻¹⁷/1.60218*10⁻¹⁹
x = 0.1245*10²
x = 12.45eV
<em>Hence the work function of the metal in eV is 12.45eV</em>