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tankabanditka [31]
4 years ago
12

What is responsible for moving weather across the U.S.?

Physics
2 answers:
lakkis [162]4 years ago
7 0
Weather gets pushed around by winds created by low and high air pressure.
olga2289 [7]4 years ago
4 0
Weather gets pushed around by winds created by low and high air pressure.
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Elements in compounds are held together by chemical what
oksano4ka [1.4K]
Bonds hold all compounds together
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3 years ago
A force of 30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the
pantera1 [17]

Answer:

Explanation:

F = k*n

F = 30N

k = ???

N = 0.73 M

F = k* N

30N = k * 0.73

k = 30N / 0.73

k = 41.1

5 0
3 years ago
Explain two reasons why sea ice so important to a polar bear.
Zolol [24]
This loss of stable old ice has set up additional losses of sea ice cover each summer because the thinner younger ice is more easily melted during the recent warmer summers. Because of their dependence upon the sea ice for food, these changes can directly affect the carrying capacity of the Arctic for polar bears. Mark this as the brainliest answer please
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3 years ago
A ski jumper travels down a slope and leaves
Serhud [2]

Question seems to be missing. Found it on google:

a) How long is the ski jumper airborne?

b) Where does the ski jumper land on the incline?

a) 4.15 s

We start by noticing that:

- The horizontal motion of the skier is a uniform motion, with constant velocity

v_x = 28 m/s

and the distance covered along the horizontal direction in a time t is

d_x = v_x t

- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity u_y = 0 and constant acceleration g=9.8 m/s^2 (where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is

d_y = \frac{1}{2}gt^2

The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is

\theta = 36^{\circ} below the horizontal

This happens when:

tan \theta = \frac{d_y}{d_x}

Substituting and solving for t, we find:

tan \theta = \frac{\frac{1}{2}gt^2}{v_x t}= \frac{gt}{2v_x}\\t = \frac{2v_x}{g}tan \theta = \frac{2(28)}{9.8} tan 36^{\circ} =4.15 s

b) 143.6 m

Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:

d_x = v_x t = (28)(4.15)=116.2 m

d_y = \frac{1}{2}gt^2 = \frac{1}{2}(9.8)(4.15)^2=84.4 m

The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{(116.2)^+(84.4)^2}=143.6 m

7 0
3 years ago
The wavelength of light in a medium is ____ the wavelength of light in a vacuum. Question 10 options: longer than shorter than e
Nookie1986 [14]

Answer:

B

Explanation:

Shorter than is the answer. Correct on the test!

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3 years ago
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