What term is defined as speed with a specific direction?

g A has all the mass at the rim, while wheel B has the mass uniformly distributed, like a solid disk. The wheels have the same m

marishachu [46]

Answer:

The second wheel

Explanation:

The torque is given by

$\tau=I\alpha$ (1)

where I is the moment of inertia and a is the angular acceleration. If we take into account the moment of inertia of a disk and a ring ()for the first wheel) we have:

$I_r=mR^2\\I_d=\frac{1}{2}mR^2$

where we used that both wheel have the same mass. By replacing in (1) we obtain:

$\alpha_r=\frac{\tau}{I_r}=\frac{\tau}{mR^2}\\\alpha_d=\frac{\tau}{I_d}=\frac{\tau}{\frac{1}{2}mR^2}=2\alpha_r\\$

Hence, the second wheel (the disk) has a greater acceleration.

hope this help!!

5 0

4 years ago

Read 2 more answers

A block of mass M=10 kg is on a frictionless surface as shown in the photo attached. And it's attached to a wall by two springs

nordsb [41]

a.

i. the speed of the block of mass when the springs are connected in parallel is 7.07 A m/s

ii. the angular velocity when the two springs are in parallel is 7.07 rad/s

b.

i. the speed of the block of mass when the springs are connected in series is 11.2 A m/s

ii. the angular velocity when the two springs are in series is 11.2 rad/s

<h3>a. </h3><h3>i. How to calculate the velocity of the mass when the springs are connected in parallel?</h3>

Since k is the spring constant of both springs = 250 N/m. The equivalent spring constant in parallel is k' = k + k

= 2k

= 2 × 250 N/m

= 500 N/m

Now since A is the maximum distance the block is pulled from its equilibrium position, the total energy of the block is E = 1/2kA

Also, 1/2k'A² = 1/2k'x² + 1/2Mv² where

k' = equivalent spring constant in parallel = 500 N/m,
A = maximum displacement of spring,
x = equilibrium position = 0 m,
M = mass of block = 10 kg and
v = speed of block at equilibrium position

Making v subject of the formula, we have

v = √[k'(A² - x²)/M]

Substituting the values of the variables into the equation, we have

v = √[k'(A² - x²)/M]

v = √[500 N/m(A² - (0)²)/10]

v = √[50 N/m(A² - 0)]

v = [√50]A m/s

v = [5√2] A m/s

v = 7.07 A m/s

So, the speed of the block of mass when the springs are connected in parallel is 7.07 A m/s

<h3>ii. The angular velocity of mass when the springs are in parallel</h3>

Since velocity of spring v = ω√(A² - x²) where

ω = angular velocity of spring,
A = maximum displacement of spring and
x = equilbrium position of spring = 0 m

Making ω subject of the formula, we have

ω = v/√(A² - x²)

Since v = 7.07 A m/s

Substituting the values of the other variables into the equation, we have

ω = v/√(A² - x²)

ω = 7.07 A m/s/√(A² - 0²)

ω = 7.07 A m/s/√(A² - 0)

ω = 7.07 A m/s/√A²

ω = 7.07 A m/s/A m

ω = 7.07 rad/s

So, the angular velocity when the two springs are in parallel is 7.07 rad/s

<h3>b. </h3><h3>i. How to calculate the velocity of the mass when the springs are connected in series?</h3>

Since k is the spring constant of both springs = 250 N/m. The equivalent spring constant in parallel is 1/k" = 1/k + 1/k

= 2/k

⇒ k" = k/2

k" = 250 N/m ÷ 2

= 125 N/m

Now since A is the maximum distance the block is pulled from its equilibrium position, the total energy of the block is E = 1/2kA

Also, 1/2k"A² = 1/2k"x² + 1/2Mv'² where

k" = equivalent spring constant in series = 125 N/m,
A = maximum displacement of spring,
x = equilibrium position = 0 m,
M = mass of block = 10 kg and
v' = speed of block at equilibrium position

Making v subject of the formula, we have

v = √[k"(A² - x²)/M]

Substituting the values of the variables into the equation, we have

v = √[k"(A² - x²)/M]

v = √[125 N/m(A² - (0)²)/10]

v = √[125 N/m(A² - 0)]

v = [√125]A m/s

v = [5√5] A m/s

v = 11.2 A m/s

So, the speed of the block of mass when the springs are connected in series is 11.2 A m/s

<h3>ii. The angular velocity of the mass when the springs are in series</h3>

Since velocity of spring v = ω√(A² - x²) where

ω = angular velocity of spring,
A = maximum displacement of spring and
x = equilbrium position of spring = 0 m

Making ω subject of the formula, we have

ω = v/√(A² - x²)

Since v = 11.2 A m/s

Substituting the values of the other variables into the equation, we have

ω = v/√(A² - x²)

ω = 11.2 A m/s/√(A² - 0²)

ω = 11.2 A m/s/√(A² - 0)

ω = 11.2 A m/s/√A²

ω = 11.2 A m/s/A m

ω = 11.2 rad/s

So, the angular velocity when the two springs are in series is 11.2 rad/s

Learn more about speed of block of mass here:

brainly.com/question/21521118

#SPJ1

3 0

2 years ago

Maggie completed a 10000-m race at an average speed of 160

nata0808 [166]

Answer:

Explanation:

The formula for calculating distance covered = Speed * time

If Maggie completed a 10000-m race at an average speed of 160

m/min, the the time taken by Maggie to complete the race will be expressed as;

Time = Distance/Speed

Time = 10000/160

Time = 62.5 minutes

If it took Tom 12.5 fewer minutes to complete the race, then the time taken by tom to finish the same race will be 62.5 - 12.5 = 50minutes.

To get Tom's average speed, we will use the same formula as above;

From Distance = Speed * Time

Speed = Distance/Time

Since both of them completed the same distance, distance covered by Tom is also 10000m

Tom's speed = 10000/50

Tom's speed = 200m/min

<em>Hence Tom's average speed is 200m/min</em>

3 0

3 years ago

Hey guys can y’all help quickly?

Naddik [55]

Answer:

Temporary? You have two options

If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).

If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).

Either way, the electron cloud will migrate towards the right side of the of your sphere.

Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.

7 0

2 years ago

The yellow wire connected to a power supply carries 12v. if the power supply provides 60w of power to the yellow wire, how much

saul85 [17]

In physics, the rate of power in Watts could be determined by multiplying the voltage in volts, by the current in Amperes. In equation, that would be

P = IV

Substituting the values into the equation,

60 W = I*12V
I = 60/12
I = 5 Amperes

Therefore, a current of 5 Amperes is passing through the yellow wire.

6 0

3 years ago