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3 years ago

What are two whole numbers that √111 fall between?

Mathematics

1 answer:

lana66690 [7]3 years ago

3 0

Answer:

I believe it would be 9 & 10. 9^2 is 81 and 10^2 is 100 which are numbers that fall in between √111.

Step-by-step explanation:

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28/29 and 30 please short explanation thanks

Bond [772]

Answer 28.

Possible values for the three factors of -3

1, -1 and 3
-1.5, 1 and 2
1.5, -1 and 2
1.5, 1 and -2

Answer 29.

The product of two nonzero integers will be less than or equal to both of the integers if they are multiplied by number itself and one or by number itself and one with negative sign.

Answer 30.

The sign of the product of three integers with the same sign will be positive or negative. If odd number of same sign is multiplied, the product will be of that sign.

(+) (+) (+) = (+)

(-) (-) (-) = (-)

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3 years ago

Solve for a and x in ax^2=48<br>

Gelneren [198K]

Answer:

$ax^2 = 48\\a = \frac{48}{x^2}$

$ax^2 = 48\\x^2 = \frac{48}{a} \\x = \frac{\sqrt{48} }{\sqrt{a} } \\x = \frac{4\sqrt{3} }{\sqrt{a}} \\x = \frac{4\sqrt{3a} }{a}$

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3 years ago

A rectangle has a width of 12 ft and a length of 4 ft.

polet [3.4K]

It's A, increased by a factor of 6.

8 0

3 years ago

Read 2 more answers

There are 14!coats and some hats there are 6 more coats than hats. How many hats are there

Allisa [31]

Answer:

There are 8 hats

Step-by-step explanation:

14-6=8

3 0

4 years ago

Read 2 more answers

The sum of a 3 digit number and a 1 digit number is 217. The product of the numbers is 642. If one number is between 200 and 225

algol [13]

Let, the numbers be "x" and "y". Consider "x" as the triple digit number.
Now, according to the question,
x + y = 217..........................equation (1)

x * y = 642............................equation (2)

Now,
Taking equation (2),
x * y = 642
y = 642 / x..................................equation (3)

Now, Taking equation (1),
$x+y=217$

Substituting the value of y from equation (3), we get,

$x+ \frac{642}{x} =217$

$\frac{x *x+642}{x} =217$

$x^{2} +642 =217*x$

$x^{2} +642 =217x$

$x^{2} +642-217x =0$

$x^{2} -217x+642 =0$

$x^{2} -3x-214x+642 =0$

$x(x-3)-214(x-3)=0$

$(x-3)(x-214)=0$

Using zero product property,
EITHER,
x - 3 = 0
x = 3
OR,
x - 214 = 0
x = 214
Since, "x" is the triple digit number, x = 214.
Now,
Taking equation (2),
x * y = 642
Substituting the value of "x" in the equation, we get,
(214) * y = 642
y = 642 / 214
y = 3

So, the numbers are 214 and 3.

5 0

3 years ago