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Llana [10]
3 years ago
6

The number of electrons in 1.6 gram CH, is:​

Chemistry
2 answers:
Alla [95]3 years ago
8 0

Answer:

6.022 x 10²³ electrons

Explanation:

Wewaii [24]3 years ago
8 0
Oh gosh oh I thought had the wrong
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Insulation is the percentage of energy that is actually used to perform work true or false
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Near the shore, winds tend to blow out toward the water at night. What drives this process?
Mila [183]

C. Convection currents in the air

Explanation:

Near the shore, winds tends to blow out towards the water at night and this is driven by convection currents in the air.

Convection occurs in fluids. Since we are dealing with wind, therefore, it is convection in air.

  • At night, the air on land is cold and under high pressure.
  • The shore area is able lose and gain heat very fast.
  • At night, since the shore is cold, the air around is cold too.
  • The ocean has high heat capacity and does not lose or gain heat easily.
  • At night, it still retains come of its heat.
  • This causes nearby winds to warm up, becomes less dense and rises.
  • The wind here is moves towards the cold land
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  • This will then set up convection currents.

learn more:

Sun's energy brainly.com/question/1140127

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8 0
3 years ago
If a 1.85 g mass of zinc produces 475 mL of gas and your balloon weighs 0.590 g and the room temperature is 23.5°C. Calculate th
ser-zykov [4K]
I came up with a required balloon volume of 476 before adding the extra 1 mL.
3 0
3 years ago
A 140.0-g sample of water at 25.0°C is mixed with 108.6 g of a certain metal at 100.0°C. After thermal equilibrium is establishe
AysviL [449]

Answer:

The value of specific heat of metal = 0.3537 \frac{KJ}{Kg K}

Explanation:

Mass of water m_{w} = 140 gm = 0.14 kg

Initial temperature of water T_{w} = 25°c = 298 K

Mass of metal m_{metal} = 108.6 gm = 0.1086 kg

Initial temperature of metal T_{metal} = 100°c = 373 K

After thermal equilibrium the final temperature  T_{f} = 29.6°c = 302.6 K

Apply energy principal

Heat lost by metal = heat gain by water  --------- (1)

⇒ Heat lost by metal = m_{metal} × C_{metal} × ( T_{metal} - T_{f} )

⇒ Heat lost by metal = 0.1086 × C_{metal} × ( 373 -302.6 )

⇒ Heat lost by metal = C_{metal} × 7.64544  KJ -------- (2)

Now

Heat gain by water = m_{w} × C_{water} × ( T_{f} - T_{w} )

⇒ Heat gain by water = 0.14 × 4.2 × ( 302.6 - 298)

⇒ Heat gain by water = 2.7048 KJ --------------------- (3)

From the energy principal

Equation 2 = equation 3

C_{metal} × 7.64544  = 2.7048

C_{metal} = 0.3537 \frac{KJ}{Kg K}

This is the value of specific heat of metal.

4 0
3 years ago
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