The number of electrons in 1.6 gram CH, is:
2 answers:
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Answer:
24.6g of NaCl
Explanation:
Expression of the reaction:
2NaCl → 2Na + Cl₂
Given parameters:
Mass of Cl₂ = 15g
Unknown:
Mass of NaCl = ?
Solution:
To solve this problem, we have to use mole relationships.
Find the number of moles of the mass of the given specie;
Number of moles =
Molar mass of Cl₂ = 2(35.5) = 71g/mol
Number of moles = = 0.21mole
Now;
From the balanced reaction equation;
1 mole of Cl₂ is produced from 2 moles of NaCl;
0.21 mole of Cl₂ will be produced from 0.21 x 2 = 0.42mole of NaCl
So,
Mass of NaCl = number of moles x molar mass
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass of NaCl = 0.42 x 58.5 = 24.6g of NaCl
Answer:
Following are the solution to this question:
Explanation:
If the draw a line perpendicular with y-axis thru the diagonal line check but it meets only one curved point, therefore the curve indicates a function not otherwise. They draw a vertical line perpendicular to the y-axis there, it just intersects one more chart point, which is why a graph is a feature:
In point a:
In point b:
Its y-axis length cut also by understanding the benefits of y-interception and the x-axis length gives the x-intercept.
In point C:
Every graph is y-axis symmetric because the left side of the column as well as the middle side of the graph is about the same.
Answer:
Mg will be the limiting reagent.
Explanation:
The balanced reaction is:
Mg + 2 HCl → MgCl₂ + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Mg: 1 mole
- HCl: 2 moles
- MgCl₂: 1 mole
- H₂: 1 mole
Being the molar mass of each compound:
- Mg: 24.3 g/mole
- HCl: 36.45 g/mole
- MgCl₂: 95.2 g/mole
- H₂: 2 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Mg: 1 mole* 24.3 g/mole= 24.3 g
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- MgCl₂: 1 mole* 95.2 g/mole= 95.2 g
- H₂: 1 mole* 2 g/mole= 2 g
0.0350 g of Mg is reacted with 10.00 mL (equal to 0.01 L) of 6 M HCl.
Molarity being the number of moles of solute that are dissolved in a certain volume, expressed as:
in units
then, the number of moles of HCl that react is:
number of moles of HCl= 6 M*0.01 L
number of moles of HCl= 0.06 moles
Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl react with 24.3 grams of Mg, 0.06 moles of HCl react with how much mass of Mg?
mass of Mg= 0.729 grams
But 0.729 grams of Mg are not available, 0.0350 grams are available. Since you have less mass than you need to react with 0.06 moles of HCl, <u><em>Mg will be the limiting reagent.</em></u>