Answer:
Cd2+ : 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10 or [Kr] 4d¹⁰
Explanation:
Before proceeding to write out the electron configuration of Cd2+, we have to obtain the electron configuration of Cadmium (Cd),
Cadmium has an atomic number of 48, this means that a neutral cadmium atom will have a total of 48 electrons surrounding its nucleus.
The electronic configuration of Cadmium is;
Cd: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10
The shorthand notation is given as;
Cd: [Kr] 4d¹⁰5s²
Cd2+ means that it has two less electrons, hence it's electron configuration is given as;
Cd2+ : 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10 or [Kr] 4d¹⁰
The continuous cycling of carbon in the earyh is known as the carbon cycle.
<h3>What is the carbon cycle?</h3>
The carbon cycle is a cycle which explains the various processes by which carbon is recycled between the atmosphere and the earth.
The constant flow of carbon on earth through organisms and the air is known as the carbon cycle. Plants absorb carbon from the atmosphere in the form of carbon dioxide. They use it for respiration and food production.
Animals consume plants, transferring carbon along the food chain.
Plants and animals respire and release carbon into air. When the animals and plants die, they are eaten by decomposers.
Carbon enters back into the atmosphere in the form of carbondio dioxide.
Therefore, the continuous cycling of carbon in the earth is known as the carbon cycle.
Learn more about carbon cycle at: brainly.com/question/25845923
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Answer:
PBr3 - Molecule , Polar
N2H2 - Molecule , (Polar in E- form and Non- polar in Z form)
C2H2 - Molecule , Non- Polar
N2 - Molecule , Polar
NCl3 - Molecule , Polar
SiF4 - Molecule , Non- Polar
NH3 - Molecule , Polar
F - Not- Molecule (atom)
H2 - Molecule and Non- Polar
Explanation:
Molecule : these are group of two or more atoms joined by strong force of attraction.
H2 is non- polar because it is homoatomic molecule.(made up of same element)
N2 is non- polar because it is homoatomic molecule.
Answer: KOH + HBr = H2O + KBr
Explanation: hope this helps
