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3 years ago

Where in the world is there a Continental Crust with Continental Crust collision?

Physics

2 answers:

Savatey [412]3 years ago

8 0

Answer:

Explanation:

betweeb the north american and eurasian planes

madreJ [45]3 years ago

3 0

The answer is C

Explanation :

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A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I

Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

$E=-\dfrac{d\phi}{dt}$

$E=-B\dfrac{dA}{dt}$

$E=-B\dfrac{A_{2}-A_{1}}{dt}$

$E=B\dfrac{A_{1}-A_{2}}{dt}$ .....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

$l=2\times 2\pi\times r_{1}$

$l=2\times 2\pi\times 0.63$

$l=7.916\ m$

The length when wire is in one loop

$l=2\pi\times r_{2}$

$7.916=2\times \pi\times r_{2}$

$r_{2}=\dfrac{7.916}{2\times \pi}$

$r_{2}=1.259\ m$

We need to calculate the initial area

$A_{1}=N\times\pi\times r_{1}^2$

Put the value into the formula

$A_{1}=2\times3.14\times(0.63)^2$

$A_{1}=2.49\ m^2$

The final area is

$A_{2}=N\times\pi\times r_{2}^2$

$A_{2}=1\times\pi\times(1.259)^2$

$A_{2}=4.98\ m^2$

Put the value of initial area and final area in the equation (I)

$E=0.219\dfrac{2.49-4.98}{0.0572}$

$E=-9.533\ V$

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0

3 years ago

An object moves in simple harmonic motion described by the equation d equals one fifth sine 2 t where t is measured in seconds a

tensa zangetsu [6.8K]

Answer:

The maximum displacement, the frequency, and the time required for one cycle are 1/5 inch, 1/π Hz and π sec.

Explanation:

Given that,

The equation of simple harmonic motion

$d = \dfrac{1}{5}\sin 2t$ .....(I)

We need to calculate the maximum amplitude

Using equation of simple harmonic motion

$y = a \sin\omega t$

Where, a = amplitude

$\omega$ =frequency

t = time

On comparing equation (I) and general equation

The amplitude is a maximum displacement traveled by a wave.

$a = \dfrac{1}{5}$

So, the maximum displacement is

$d= \dfrac{1}{5}\ inch$

We need to calculate the frequency

$\omega=2\pi f$

$f = \dfrac{1}{\pi}\ Hz$

We need to calculate the time required for one cycle

$t =\dfrac{1}{f}$

$t =\pi\ sec$

Hence, The maximum displacement, the frequency, and the time required for one cycle are 1/5 inch, 1/π\ Hz and π\ sec.

3 0

3 years ago

The electrical loads in _____ circuits each have the same voltage drop, with equals the total applied voltage of the circuit.

Vesna [10]

Answer:

The electrical loads in parallel circuits each have the same voltage drop, with equals the total applied voltage of the circuit.

Explanation:

I did some research and the voltage drop across any branch of a parallel circuit is the same as the applied voltage.

3 0

2 years ago

Which light is most sensitive to the eyes?

san4es73 [151]

Answer:

Our eyes are most sensitive to the wavelengths corresponding to the yellow and green colors of the spectrum. Flashy signs and some fire engines are painted in a yellowish-green color to attract our attention.

6 0

3 years ago

An object is moving north with an initial velocity of 14 m/s accelerates 5m/s for 20 seconds. What is the final velocity of the

olga2289 [7]

Use the kinematic equation: Vf=Vi+at

Then plug;

Vi=14 m/s

a=5 m/s²

t=20 s. Therefore;

Vf=14+(5*20)

Vf=114 m/s.

6 0

3 years ago