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svetlana [45]
3 years ago
10

An object moving with initial velocity 10 m/s is subjected to a uniform acceleration of 8 m/s ^² . The displacement in the next

2 s is: (a) 0m (b) 36 m (c) 16 m (d) 4 m​
Physics
1 answer:
Greeley [361]3 years ago
8 0
365 Everyday Value, Organic Creamy Peanut Butter. Net Carbs: 4 grams per serving. ...
Classic Peanut Butter by Justin's. Net Carbs: 5 grams. ...
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0.001225 kg/L x 720 000 000L =?
I am Lyosha [343]

Answer:

0.001225 kg/L × 720 000 000 L = 882000 kg

Explanation:

Given:

The equation to solve is given as:

0.001225 kg/L × 720 000 000 L = ?

Let us write each term of the product in terms of power of 10.

As 0.001225 has 6 digits after the decimal place, therefore, we use the exponent 6 for 10 and the sign is negative. This gives,

0.001225\ kg/L = 1225\times 10^{-6}\ kg/L

Now, for 720000000 L there are 6 zeros after 720. So, we use exponent 6 but with a positive sign. This gives,

720000000\ L=720\times 10^{6}\ L

Now, finding the product, we get:

0.001225\ kg/L\times 720000000\ L\\\\=1225\times 10^{-6}\ kg/L\times 720\times 10^6\ L\\\\=(1225\times 720)\times (10^6\times 10^{-6})\ (\frac{kg}{L}\times L)\\\\=882000\times 10^{6-6}\ kg\\\\=882000\times 10^0\ kg\\\\=882000\times 1\ kg\\\\=882000\ kg

Therefore, the product is equal to:

0.001225 kg/L × 720 000 000 L = 882000 kg

6 0
4 years ago
An object of mass 10 kg is in a circular orbit of radius 10 m at a
Paladinen [302]
A :-) F = mv^2 by t
Given - m = 10 kg
r = 10 m
v = 10 m/s
Solution -
F = mv^2 by t
F = 10 x 10^2 by 10
F = 10 x 100 by 10
( cut 10 and 10 because 10 x 1 = 10 )
F = 100 N

.:. The centripetal force is 100 N
8 0
3 years ago
In 1666 at the age of 23, what scientist
scoray [572]

Answer:

<h3>B - Isaac Newton</h3>

Explanation:

He first thought of his system of gravitation which he hit upon by observing an apple fall from a tree,

The incident occurring in the late summer of 1666.

3 0
3 years ago
You are loading a toy dart gun, which has two settings, the more powerful with the spring compressed twice as far as the lower s
Amiraneli [1.4K]

Answer:

option A

Explanation:

given,

compression for lower setting = x

work done to compress in lower setting = 5 J

compression in higher setting, x' = 2 x

work done in higher setting = ?

Work done in compression of spring at lower setting

W = \dfrac{1}{2}kx^2

5 = \dfrac{1}{2}kx^2............(1)

Work done in compression of spring at higher setting

W' = \dfrac{1}{2}kx'^2

W'= \dfrac{1}{2}k(2x)^2

W'= 4\times \dfrac{1}{2}kx^2

W'= 4\times W

from equation (1)

W'= 4\times 5

    W' = 20 J

Work take for the higher setting is equal to 20 J

Hence, the correct answer is option A

4 0
3 years ago
An asteroid, whose mass is 3.6 × 10-4 times the mass of Earth, revolves in a circular orbit around the Sun at a distance that is
frosja888 [35]

Answer:

a) 2.02 years

b) 8.1 x 10⁻⁸.

Explanation:

Time period of a rotating body T² is proportional to radius of orbit R³ So

T₁² / T₂² = R₁³ /R₂³ ( T₁ and R₁ is time period and radius of orbit of the earth .)

1² / T₂² =( 1/1.6)³

T₂ = 2.02 years.

Kinetic energy of an orbiting body = 1/2 m v₀² ( v₀ is orbital speed)

= 1/2 m x 2 g R = m x G m/R² X R= m² x G /R

Kinetic energy of asteroid K₁ / kinetic energy of earth K₂ =

(mass of asteroid/mass of earth)² x( radius of earth / radius of asteroid)

=( 3.6 x 10⁻⁴)² x 1/1.6 = 8.1 x 10⁻⁸ .

7 0
3 years ago
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