Mass of C = 12g
mass of H = 1g
mass of O = 16g
mass of C2H5OH = 46g = 1 mole
1 mole of C2H5OH ------------ 46g
x moles of C2H5OH ----------- 230g
x = 5 moles of C2H5OH
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of C = 12g
mass of H = 1g
mass of C2H4 = 28g = 1 mole
1 mole of C2H4 -------------- 28g
x moles of C2H4 ------------- 560g
x = 20 moles of C2H4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of S = 32g
mass of O = 16g
mass of SO2 = 64g = 1 mole
1 mole of SO2--------------------- 64g
x mole of SO2 -------------------- 0,64g
x = 0,01 moles of SO2
Answer:
Molar Mass
Explanation:
Plz brainliest lemme know if wrong (:
Answer:
Greater than
Less than
Greater than
Less than
Greater than
Explanation:
The dipole moment is the difference of electronegativity between the atoms in a molecule, and the total is the sum of the dipole moments of the bonds. So, it depends on the geometry of the molecule. When the dipole moment is 0 the molecule is nonpolar, when it is different from 0 the molecule is polar.
Both ClO₂ and SO₂ have angular geometry because there are lone pairs of electrons in the central atom (Cl and S), but Cl has a higher value of electronegativity than S, so the dipole moment must be greater.
SiF₄ is a nonpolar molecule, which has tetrahedral geometry and no lone pairs at the central atom. SF₄ has lone pairs at the central atom, and then the molecule is polar, so the dipole moment of SiF₄ is less than of SF₄.
The SO₃ molecule has no lone pairs at the central atom and has trigonal geometry, so it's a nonpolar molecule. SO₂ has angular geometry and it's a polar molecule, so the dipole moment of SO₂ is greater.
BeCl₂ has a linear geometry and is a nonpolar molecule. SCl₂ has an angular geometry, and it's a polar molecule, so the dipole moment of BeCl₂ is less than the dipole moment of SCl₂.
Oxygen has a higher electronegativity than the sulfur, and both molecules are polar with angular geometry, so the dipole moment of H₂O is greater.
Answer:
pH = 2.97
Explanation:
Aspirin, (HC₉H₇O₄), is in equilibrium with water, thus:
HC₉H₇O₄(aq) + H₂O(l) ⇄ C₉H₇O₄⁻(aq) + H₃O⁺(aq)
Ka = 3.0x10⁻⁴ = [C₉H₇O₄⁻][H₃O⁺] / [HC₉H₇O₄]
When you add 0.0050M of aspirine, the solution reach equilibrium when concentrations are:
[HC₉H₇O₄] = 0.0050M - x
[C₉H₇O₄⁻] = x
[H₃O⁺] = x
Replacing in Ka formula:
3.0x10⁻⁴ = [x][x] / [0.0050-x]
1.5x10⁻⁶ - 3.0x10⁻⁴X = X²
X² + 3.0x10⁻⁴X - 1.5x10⁻⁶ = 0
Solving for x:
x = - 0.00138 → False answer. There is no negative concentrations
x = 0.00108 → Right answer
As [H₃O⁺] = x; [H₃O⁺] = 0.00108M.
pH = -log[H₃O⁺]
<em>pH = 2.97</em>
