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DedPeter [7]
3 years ago
7

Will give brainliest for right answers please help

Mathematics
2 answers:
vichka [17]3 years ago
7 0

Answer: I just took the test and got 100%

1. (B) III, 7pi/18

2. (B) 150*

3. (B) -4/3

4. (A)   (D)

5. (B) sec3pi/2

These are 100%, feel free to mark as brainliest :)

Scrat [10]3 years ago
6 0
1. A
2. B
3. B
4. A
5. C
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Selina is playing a game that uses the spinner below.
MatroZZZ [7]

Answer:

A) 12.5%

B) 50%

C) 50%

Step-by-step explanation:

For A, 7 is one of the 8 possibilities (1/8). 1/8 of 100 is 12.5, so your chance of spinning a 7 is 12.5%

For B, even numbers are 4/8 or 1/2 of your options. 1/2 of 100 is 50, so your chance of spinning an even number is 50%

For C, there are 4 out of 8 numbers that are prime (2,3,5, & 7).

4/8 or 1/2 of 100 is 50, so your chance of spinning a prime number is 50%

hope this helps

4 0
3 years ago
Which choices are equivalent to the fraction below? Check all that apply.<br> 20/24
laiz [17]

Answer:

5/6

Step-by-step explanation:

20 divide by 2 is 10

24 divide by 2 is 12

then have 10/12

10 divide by 2 is 5

12 divide by 2 is 6

answer is 5/6

7 0
3 years ago
1.5(x−2)−3(2−x)
adell [148]

Answer:

1. x = 2

2. x = 61/25

Step-by-step explanation:

Solve for x:

5 (x - 2) - 3 (2 - x) = 0

-3 (2 - x) = 3 x - 6:

3 x - 6 + 5 (x - 2) = 0

5 (x - 2) = 5 x - 10:

5 x - 10 + 3 x - 6 = 0

Grouping like terms, 5 x + 3 x - 10 - 6 = (3 x + 5 x) + (-6 - 10):

(3 x + 5 x) + (-6 - 10) = 0

3 x + 5 x = 8 x:

8 x + (-6 - 10) = 0

-6 - 10 = -16:

8 x + -16 = 0

Add 16 to both sides:

8 x + (16 - 16) = 16

16 - 16 = 0:

8 x = 16

Divide both sides of 8 x = 16 by 8:

(8 x)/8 = 16/8

8/8 = 1:

x = 16/8

The gcd of 16 and 8 is 8, so 16/8 = (8×2)/(8×1) = 8/8×2 = 2:

Answer:  x = 2

_____________________________

Solve for x:

Solve for x:

3 (2 x - 7) + (7 x + 2)/3 = 0

Put each term in 3 (2 x - 7) + (7 x + 2)/3 over the common denominator 3: 3 (2 x - 7) + (7 x + 2)/3 = (9 (2 x - 7))/3 + (7 x + 2)/3:

(9 (2 x - 7))/3 + (7 x + 2)/3 = 0

(9 (2 x - 7))/3 + (7 x + 2)/3 = (9 (2 x - 7) + (7 x + 2))/3:

(9 (2 x - 7) + 2 + 7 x)/3 = 0

9 (2 x - 7) = 18 x - 63:

(18 x - 63 + 7 x + 2)/3 = 0

Grouping like terms, 18 x + 7 x - 63 + 2 = (18 x + 7 x) + (2 - 63):

((18 x + 7 x) + (2 - 63))/3 = 0

18 x + 7 x = 25 x:

(25 x + (2 - 63))/3 = 0

2 - 63 = -61:

(25 x + -61)/3 = 0

Multiply both sides of (25 x - 61)/3 = 0 by 3:

(3 (25 x - 61))/3 = 3×0

(3 (25 x - 61))/3 = 3/3×(25 x - 61) = 25 x - 61:

25 x - 61 = 3×0

0×3 = 0:

25 x - 61 = 0

Add 61 to both sides:

25 x + (61 - 61) = 61

61 - 61 = 0:

25 x = 61

Divide both sides of 25 x = 61 by 25:

(25 x)/25 = 61/25

25/25 = 1:

Answer: x = 61/25

7 0
3 years ago
16+24/8-6 is equal to________
Yuliya22 [10]

Answer: The answer is 28. Hope this helps:)

8 0
3 years ago
Read 2 more answers
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

x^3y'' + 2x^2y' + 4y

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ;  x=x_o is  located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0

y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0

The standard form of the differential equation is :

\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0

Thus;

P(x) = \dfrac{2}{x}

Q(x) = \dfrac{4}{x^3}

The zeros of x,x^3  is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x)    and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = x*\dfrac{2}{x}

p(x) = 2

q(x) = x²Q(x)

q(x) = x^2 * \dfrac{4}{x^3}

q(x) =\dfrac{4}{x}

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic  at x = 0

Q(x) = \dfrac{4}{x^3}  do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0
3 years ago
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