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3 years ago

Lividity in a dead body is caused by capillaries decaying due to de-oxygenation.

2 answers:

5 0

Livor mortis refers to the bluish-purple discoloration (lividity) under the skin of the lower body parts due to gravitation of blood after death. ... Dark pinpoint spots (Tardieu spots) are seen when capillaries rupture due to increased gravitational pressure (e.g. in the legs of a hanged person)

lions [1.4K]3 years ago

5 0

Explanation: Lividity is unnatural color or discoloration of the skin after death. It starts within 20-30 minutes of death, but is not visible by human eye until two hours. Amount of reduced haemoglobin determines the intensity of color. Capillaries bursts because of increased gravity.The body parts which are in contact with any object or ground are not affected by this because capillaries are compressed.

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3 years ago

The study of all chemicals containing carbon is called ?

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3 years ago

The heat of fusion AH, of ethyl acetate (C4H802) is 10.5 kinol. Calculate the change in entropy as when 398. g of ethy, acetate

Hitman42 [59]

Answer: The entropy change of the ethyl acetate is 133. J/K

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ethyl acetate = 398 g

Molar mass of ethyl acetate = 88.11 g/mol

Putting values in above equation, we get:

$\text{Moles of ethyl acetate}=\frac{398g}{88.11g/mol}=4.52mol$

To calculate the entropy change for different phase at same temperature, we use the equation:

$\Delta S=n\times \frac{\Delta H_{fusion}}{T}$

where,

$\Delta S$ = Entropy change = ?

n = moles of ethyl acetate = 4.52 moles

$\Delta H_{fusion}$ = enthalpy of fusion = 10.5 kJ/mol = 10500 J/mol (Conversion factor: 1 kJ = 1000 J)

T = temperature of the system = $84.0^oC=[84+273]K=357K$

Putting values in above equation, we get:

$\Delta S=\frac{4.52mol\times 10500J/mol}{357K}\\\\\Delta S=132.9J/K$

Hence, the entropy change of the ethyl acetate is 133. J/K

7 0

3 years ago

How would you prepare 1.00 L of a 0.50 M solution of each of the following?

Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

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In this case, for the dilution process from concentrated 12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

$n_1=n_2$