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3 years ago

If a gun is found in water, what should investigators do to transport it to the lab?

2 answers:

8 0

<span>Most items of evidence will be collected in paper containers such as packets, envelopes, and bags. Liquid items can be transported in non-breakable, leakproof containers. Arson evidence is usually collected in air-tight, clean metal cans. Only large quantities of dry powder should be collected and stored in plastic bags. Moist or wet evidence (blood, plants, etc.) from a crime scene can be collected in plastic containers at the scene and transported back to an evidence receiving area if the storage time in plastic is two hours or less and this is done to prevent contamination of other evidence. Once in a secure location, wet evidence, whether packaged in plastic or paper, must be removed and allowed to completely air dry. That evidence can then be repackaged in a new, dry paper container. UNDER NO CIRCUMSTANCES SHOULD EVIDENCE CONTAINING MOISTURE BE PACKAGED IN PLASTIC OR PAPER CONTAINERS FOR MORE THAN TWO HOURS. Moisture allows the growth of microorganisms which can destroy or alter evidence.

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sdas [7]3 years ago

5 0

Keep the gun in some of the water, the prints could still be on the gun if any crime was done. drying it out will only add prints to it.

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If Kc = 4.0×10−2 for PCl3(g)+Cl2(g)⇌PCl5(g) at 520 K , what is the value of Kp for this reaction at this temperature?

Flauer [41]

Here we have to get the $K_{p}$ of the reaction at 520 K temperature.

The $K_{p}$ of the reaction is 1.705 atm

We know the relation between $K_{p}$ and $K_{c}$ is $K_{p}=K_{c}(RT)^{N}$ , where $K_{p}$ = The equilibrium constant of the reaction in terms of partial pressure, $K_{c}$ = The equilibrium constant of the reaction in terms of concentration and N = number of moles of gaseous products - Number of moles of gaseous reactants.

Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅

Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole

The given value of $K_{c}$ is 4.0×10⁻²

The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.

On plugging the values in the equation we get,

$K_{p} = 4.0 X 10^{-2}(0.082X520)^{1}$

Or, $K_{p}$ = 1.705 atm

Thus, the $K_{p}$ of the reaction is 1.705 atm

7 0

3 years ago

What did Bohr’s model of the atom do that Rutherford’s model did not?

Dafna1 [17]

Answer:

The last option

Explanation:

The Bohr model was an attempt to explain atomic hydrogen's spectrum. This was done by establishing energy levels of separate electron orbits in the atom.Thos model was followed by the Schrödinger model.

5 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL GIVE YOU BRAINLIEST PLEASE

g100num [7]

Answer:

the answer is the second choice actual force

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3 years ago

Explain why the air in Earth's atmosphere is a mixture, not a compound. Brainiest offered need it by 6:45!!!

Georgia [21]

Answer:

air is not a mixture because of scientists freezing it and finding different liquids, it is a mixture because the compounds that make up air e.g. oxygen (o2), Carbon dioxide (co2) and the most important Nitrogen which is an element and makes up 78.09% of air are not chemically bound in the way that compounds are

Explanation:

8 0

3 years ago

Construct a three-step synthesis of 1,2-epoxycyclopentane from cyclopentanol by dragging the appropriate formulas into the bins.

vladimir2022 [97]

Answer:

(1) Bromination, (2) E2 elimination and (3) epoxidation

Explanation:

In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with $PBr_{3}$

In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene

In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane

Full reaction scheme has been shown below

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3 years ago