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anastassius [24]
3 years ago
5

An ammonia buffer solution contains 0.20 M N H 4 and 0.24 M N H 3 . The pKa of ammonium is 9.24. What is the pH of the buffer

Chemistry
1 answer:
arsen [322]3 years ago
6 0

Answer:

pH = 0.32

Explanation:

To solve this problem we use the <em>Henderson-Hasselbach equation</em>:

  • pH = pKa + log\frac{[A^-]}{[HA]}

In this case

  • pKa = 9.24
  • [A⁻] is [NH₃], as it is the conjugate base of a weak acid
  • [HA] is [NH₄⁺], as it is a weak acid

So now we just <u>compute the data in the equation</u>

  • pH = 9.24 + log \frac{0.24M}{0.20M}
  • pH = 0.32
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The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
Dennis_Churaev [7]
The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:

atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g

So one mole of C4H10 would have a mass of 58.12 g.

Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles

2.50g *1 mole/ 58.12 g = .043014 moles of C4H10

You know that for every mole of C4H10, there are 4 moles of Carbon

so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r

6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:

atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g

So one mole of C4H10 would have a mass of 58.12 g.

Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles

2.50g *1 mole/ 58.12 g = .043014 moles of C4H10

You know that for every mole of C4H10, there are 4 moles of Carbon

so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r

6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.

Hope it helps
6 0
3 years ago
Read 2 more answers
28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark. F
djyliett [7]

Answer:

Density if iron shot = 7.92 g/ml (2 sig. figs.)

Explanation:

By definition, density is mass per unit volume. That is,

Density (D) = mass(m)/Volume(V)

mass(m) = 28.5g (given)

Volume(V, of iron shot) = 49.10ml - 45.5ml = 3.6ml

Substitutuing into D = m/V = 28.5g/3.6ml = 7.9166667 g/ml (calc.ans)

≅ 7.92 g/ml (2 sig. figs.)

Hope this helps. :-)

7 0
3 years ago
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