Answer:
1019.27 g.
Explanation:
- For the balanced reaction:
<em>2Na + Cl₂ → 2NaCl,</em>
It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.
- Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:
2 moles of Na need → 1 mol of Cl₂, from the stichiometry.
57.5 moles of Na need → ??? mol of Cl₂.
<em>∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na =</em> (1 mol)(57.5 mol)/((2 mol) <em>= 28.75 mol.</em>
<em>∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) =</em> (28.75 mol)(35.453 g/mol) <em>= 1019.27 g.</em>
I believe the correct answer from the choices listed above is the third option. It would be chromium (Cr) that is a transition metal. The 38 elements in groups 3 through 12 of the periodic table are called "transition metals<span>". Hope this answers the question. Have a nice day.</span>
If you never stopped you could walk 17918.2 miles
Assuming that the O2 gas acts like an ideal gas, we find
the following expression to be approximates of the behaviour of this gas:
<span>P V = n R T --->
1</span>
where,
P = pressure exerted by the gas
V = volume occupied
n = number of moles
R = universal gas constant
T = absolute temperature
Further, we assume that the number of moles and the
temperature are constant, hence reducing equation 1 into the form:
<span>P V = k --->
2</span>
where k is a constant. Therefore we can equate two
states:
P1 V1 = P2 V2
Since P1, V1 and V2 are given and we are to look for P2:
25 mL * 2 atm = 100 mL * P2
<span>P2 = 0.5 atm</span>
