Question

For the reaction 2Na + Cl2 → 2NaCl, how many grams of chlorine gas are required to react completely with 57.5 mol of sodium?

Answer 1

Answer:

1019.27 g.

Explanation:

• For the balanced reaction:

2Na + Cl₂ → 2NaCl,

It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.

• Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:

2 moles of Na need → 1 mol of Cl₂, from the stichiometry.

57.5 moles of Na need → ??? mol of Cl₂.

∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na = (1 mol)(57.5 mol)/((2 mol) = 28.75 mol.

∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) = (28.75 mol)(35.453 g/mol) = 1019.27 g.