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larisa [96]
3 years ago
14

You measure distances from the center of a diffraction pattern (y) to a series of dark fringes on a screen that is 0.3000 ± 0.00

05 m away from the 0.04-mm wide slit you are using to create the pattern. You create a plot of y (in m) vs m and get a slope for the best-fit line of 0.005525 ± 8.175 10-6. What is the wavelength of the laser you used to collect the data?
Physics
1 answer:
mojhsa [17]3 years ago
5 0

To solve this problem it is necessary to apply the concepts related to Slit Diffraction.

The expression for separation between fringes is given by,

d= \frac{\lambda D} {a}

Where,

\lambda = Wavelength

d = Separation between fringes

a = Slit width

D = Distance between the slits

Re-arrange to find \lambda, we have that

\lambda = \frac{da}{D}

Replacing with our values we have

\lambda = \frac{(0.005575)(4*10^-5)}{0.3}

\lambda = 743.15*10^{-9}

\lambda = 743.14nm

Therefore  the wavelength of the laser you used to collect the data is 743.14nm

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ipn [44]

Answer:

Energy

Explanation:

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3 0
3 years ago
Use your calculator to evaluate -3.7 meter/second-13.9 meter/second 21.4 second-72 second
cluponka [151]

Answer :

(-3.7 meter/second) - (13.9 meter/second) = -17.6 meter/second

(21.4 second) - (72 second) = -50.6 second

Explanation :

(1) As we are given the expression :

(-3.7 meter/second) - (13.9 meter/second)

Now we have to evaluate this expression, we get:

⇒ -17.6 meter/second

(2) As we are given the expression :

(21.4 second) - (72 second)

Now we have to evaluate this expression, we get:

⇒ -50.6 second

6 0
3 years ago
Select the statement that correctly lists the forces from strongest to weakest. (2 points)
Vilka [71]

Strong Nuclear force: it is the short range force and strongest fundamental force in all type of forces.

Electromagnetism: this is the force due to magnetic and electric behavior of the particles. It is moderate type of force and its range is more than Nuclear force.

Weak Nuclear Force: This force is also short range force which act between the nucleoside. But this force is also moderate type of force

Gravitational force: this force is between two point masses and least order of force. also the range of this force is upto infinite.

so the correct order of this fundamental force is

<em>strong nuclear, electromagnetism, weak nuclear, gravitational</em>

5 0
3 years ago
An object is moving along a straight line, and the uncertainty in its position is 1.90 m.
just olya [345]

Answer:

2.78\times 10^{-35}\ \text{kg m/s}

6.178\times 10^{-34}\ \text{m/s}

0.31\times 10^{-4}\ \text{m/s}

Explanation:

\Delta x = Uncertainty in position = 1.9 m

\Delta p = Uncertainty in momentum

h = Planck's constant = 6.626\times 10^{-34}\ \text{Js}

m = Mass of object

From Heisenberg's uncertainty principle we know

\Delta x\Delta p\geq \dfrac{h}{4\pi}\\\Rightarrow \Delta p\geq \dfrac{h}{4\pi\Delta x}\\\Rightarrow \Delta p\geq \dfrac{6.626\times 10^{-34}}{4\pi\times 1.9}\\\Rightarrow \Delta p\geq 2.78\times 10^{-35}\ \text{kg m/s}

The minimum uncertainty in the momentum of the object is 2.78\times 10^{-35}\ \text{kg m/s}

Golf ball minimum uncertainty in the momentum of the object

m=0.045\ \text{kg}

Uncertainty in velocity is given by

\Delta p\geq m\Delta v\geq 2.78\times 10^{-35}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{m}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{0.045}\\\Rightarrow \Delta v\geq 6.178\times 10^{-34}\ \text{m/s}

The minimum uncertainty in the object's velocity is 6.178\times 10^{-34}\ \text{m/s}

Electron

m=9.11\times 10^{-31}\ \text{kg}

\Delta v\geq \dfrac{\Delta p}{m}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{9.11\times 10^{-31}}\\\Rightarrow \Delta v\geq 0.31\times 10^{-4}\ \text{m/s}

The minimum uncertainty in the object's velocity is 0.31\times 10^{-4}\ \text{m/s}.

6 0
2 years ago
C
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Answer:

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3 0
3 years ago
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