What is sediment and debris, and what role does it play in the way sedimentary rock forms?

2 answers:

6 0

Sediments are pieces of rock that come from other rocks that were eroded or broken by wind, water or other mechanical forces. Debris are pieces of other materials that were also swept away.

When these sediments and debris settle, they create layers. These layers are called beds. In time, several layers of other sediments and debris form on top of each other which press down onto the previous layers. Because of the pressure from the weight of the newer layers, the sediments and debris are pressed together and go through cementation. These then produce sedimentary rocks.

Metamorphic rocks form when rocks undergo heat and pressure. The heat comes from the friction resulting from the pressure. The heat can also come from radioactive decay. The rocks then slowly bake into new rocks called metamorphic rocks.

Igneous rocks form when magma and lava cool down. Magma is molten fluid found beneath the surface of the Earth. Lava is magma that has reached the surface of the Earth. When they cool down, they crystallize which make igneous rocks.

The difference between intrusive and extrusive igneous rocks is that one is made beneath the Earth and the other is made on the surface of the Earth. When magma cools, it takes a long time and the product of this cooling are intrusive igneous rocks. On the other hand, extrusive igneous rock is the result of lava cooling, which does not take as long to cool down because it occurs on the surface of the Earth.

Examples of the following types of rocks:

Sedimentary: limestone, sandstone, siltstone
Metamorphic: Marble, gneiss, slate
Igneous: Gabbro (intrusive), granite (Intrusive), obsidian (extrusive)

prohojiy [21]2 years ago

6 0

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. Inside a conducting sphere of radius 1.2 m, there is a spherical cavity of radius 0.8 m. At the center of the cavity is a poin

MAVERICK [17]

Answer:

E = 1,873 10³ N / C

Explanation:

For this exercise we can use Gauss's law

Ф = E. dA = $q_{int}$ / ε₀

Where q_{int} is the charge inside an artificial surface that surrounds the charged body, in this case with the body it has a spherical shape, the Gaussian surface is a wait with radius r = 1.35 m that is greater than the radius of the sphere.

The field lines of the sphere are parallel to the radii of the Gaussian surface so the scald product is reduced to the algebraic product.

The surface of a sphere is

A = 4π r²

E 4π r² = q_{int} /ε₀

The net charge within the Gauussian surface is the charge in the sphere of q1 = + 530 10⁻⁹ C and the point charge in the center q2 = -200 10⁻⁹ C, since all the charge can be considered in the center the net charge is

q_{int} = q₁ + q₂

q_{int} = (530 - 200) 10⁻⁹

q_{int} = 330 10⁻⁹ C

The electric field is

E = 1 / 4πε₀ q_{int} / r²

k = 1 / 4πε₀

E = k q_{int}/ r²

Let's calculate

E = 8.99 10⁹ 330 10⁻⁹/ 1.32²

E = 1,873 10³ N / C

7 0

3 years ago