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Nutka1998 [239]
3 years ago
14

The density of liquid mercury is 13.6 g/mL. What is its density in units of lb/in​3​? (2.5 cm+1 in., 2.205 lbs= 1 kg., 1000 g =1

kg, 1 mL = 1 cm3).
Chemistry
1 answer:
shusha [124]3 years ago
3 0

Answer:

Density, \rho=0.49\ lb/in^3

Explanation:

It is given that the density of liquid mercury is 13.6 g/mL. We need to convert the density into lb/in³.

We know that,

2.205 lbs= 1 kg

1 g = 0.0022 lb

1 mL = 0.0610 in³

13.6\ \dfrac{g}{mL}=13.6\times \dfrac{0.0022\ lb}{0.0610\ in^3}\\\\=0.49\ lb/in^3

So, the density of liquid mercury is 0.49\ lb/in^3.

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Aqueous concentrated nitric acid is 69% hno3 by weight and has a density of 1.42 g/ml.
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Answer: -

15.55 M

35.325 molal

Explanation: -

Let the volume of the solution be 1000 mL.

Density of nitric acid = 1.42 g/ mL

Total Mass of nitric acid Solution = Volume of nitric acid x Density of nitric acid

= 1000 mL x 1.42 g/ mL

= 1420 g.

Percentage of HNO₃ = 69%

Amount of HNO₃ = \frac{69} {100} x 1420 g

= 979.8 g

Molar mass of HNO₃ = 1 x 1 + 14 x 1 + 16 x 3 = 63 g /mol

Number of moles of HNO₃ = \frac{979.8 g}{63 g/ mol}

= 15.55 mol

Molarity is defined as number of moles per 1000 mL

We had taken 1000 mL as volume and found it to contain 15.55 moles.

Molarity of HNO₃ = 15.55 M

Mass of water = Total mass of nitric acid solution - mass of nitric acid

= 1420 - 979.8

= 440.2 g

So we see that 440.2 g of water contains 15.55 moles of HNO₃

Molality is defined as number of moles of HNO₃ present per 1000 g of water.

Molality of HNO₃ = \frac{15.55 x 1000}{440.2}

= 35.325 molal

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