Answer:
A. High electrical conductivity
Explanation:
solid silver isn't brittle, it has a high melting point, and its not a good insulator.
(a) The nature of bond between A and B is an ionic bond.
(b) The two main properties of the ionic compounds are:
- Ionic Compounds have high boiling and melting points as they're very strong and require a lot of energy to break.
- The electrostatic forces of attraction between oppositely charged ions lead to the formation of ions.
(c) If the ionic compound is dissolved in water, the ions in the solid separate and disperse uniformly
<h3>What is an ionic compound?</h3>
Ionic compounds contain ions and are held together by the attractive forces among the oppositely charged ions.
An ionic bond is formed by the complete transfer of some electrons from one atom to another. The atom losing one or more electrons becomes a cation—a positively charged ion.
In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.
When ionic compounds dissolve in water, the ions in the solid separate and disperse uniformly throughout the solution.
Learn more about the ionic bond here:
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Answer:
molality of sodium ions is 1.473 m
Explanation:
Molarity is moles of solute per litre of solution
Molality is moles of solute per kg of solvent.
The volume of solution = 1 L
The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams
The mass of solute = moles X molar mass of sodium phosphate = 0.65X164
mass of solute = 106.6 grams
the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg
the molality = 
Thus molality of sodium phosphate is 0.491 m
Each sodium phosphate of molecule will give three sodium ions.
Thus molality of sodium ions = 3 X 0.491 = 1.473 m
Answer:
Filament
Explanation:
The style, ovary and the stigma is present in the pistil thus the gilament is not a part of the pistil
Empirical formula is the simplest ratio of whole numbers of components in a compound.
Assuming for 100 g of the compound
Cu As S
mass 48.41 g 19.02 g 32.57 g
number of moles 48.41 / 63.5 g/mol 19.02 / 75 g/mol 32.57 / 32 g/mol
= 0.762 mol = 0.2536 mol = 1.018 mol
divide by the least number of moles
0.762 / 0.2536 0.2536 / 0.2536 1.018 / 0.2536
= 3.00 = 1.00 = 4.01
once they are rounded off
Cu - 3
As - 1
S - 4
therefore empirical formula is Cu₃AsS₄
