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Drupady [299]
3 years ago
9

The watt is a unit of potential energy. True or False?

Physics
1 answer:
ryzh [129]3 years ago
7 0
The best and most correct answer among the choices provided by the question is FALSE<span>.
</span>
Watt is the unit of POWER. <span>Power is the work done in a unit of time.</span>

Hope my answer would be a great help for you.    
If you have more questions feel free to ask here at Brainly.
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Q 28.7: A strip 1.2 mm wide is moving at a speed of 25 cm/s through a uniform magnetic field of 5.6 T. What is the maximum Hall
Zinaida [17]

Answer:the  maximum Hall voltage across the strip= 0.00168 V.

Explanation:

The Hall Voltage is calculated using

Vh= B x v x  w

Where

B is the magnitude of the magnetic field, 5.6 T

v is the speed/  velocity of the strip, = 25 cm/s  to m/s becomes 25/100=0.25m/s

and w is the width of the strip=  1.2 mm to meters becomes 1.2 mm /1000= 0.0012m

 Solving

Vh= 5.6T x 0.25m/s x 0.0012m

=0.00168T.m²/s

=0.00168Wb/s

=0.00168V

Therefore, the  maximum Hall voltage across the strip=0.00168V

3 0
3 years ago
The number density of gas atoms at a certain location in the space above our planet is about 1.05 × 1011 m-3, and the pressure i
Anettt [7]

To solve this problem we will apply the concepts given by the ideal gas equation, which mathematically can be described as

PV = NkT

Here

P = Pressure

V = Volume

N = Number of atoms of molecules

k = Bolzmann constant

T = Temperature

Rearranging to find the temperature we have

T = \frac{PV}{Nk}

Since the value given in the exercise is a unit of atoms per volume, we will readjust the equation like this

T = \frac{P}{\frac{N}{V}k}

Replacing we have,

T = \frac{(2.7*10^{-10}N/m^2)}{(1.05*10^{11}/m^3)(1.38*10^{-23}J/K)}

T = 186.3K

T = -86.81\°C

Therefore the temperature is -86.81°C or 186.3K

7 0
3 years ago
Two people were pulling this thing with 560 Newton. Now they are using a rope with 50°. How much Newton would they need to pull
Brums [2.3K]

Answer:

10 N

Explanation:

While many people would like to simply add the forces from each end to get a total force, this is fundamentally incorrect.

MIGHT BE TOTALLY WRONG

4 0
3 years ago
About 30 % of earth’s water found In
Illusion [34]

Answer:

30 percent is found in ground water.

6 0
3 years ago
(a) How many kilograms of water must evaporate from a 60.0-kg woman to lower their body temperature by 0.750ºC?
Mrrafil [7]

Answer:

69.69 g

Explanation:

Evaporation of water will take out latent heat of vaporization.  Let the mass of water be m and latent heat of vaporization of water be 2260000 J per kg

Heat taken up by evaporating water

= 2260000 x m J

Heat lost by body

= mass x specific heat of body x drop in temperature

60 x 3500 x .750  ( specific heat of human body is 3.5 kJ/kg.k)

= 157500 J

Heat loss = heat gain

2260000 m= 157500

m = .06969 kg

= 69.69 g

5 0
4 years ago
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