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muminat
3 years ago
8

A scientist measuring the resistivity of a new metal alloy left her ammeter in another lab, but she does have a magnetic field p

robe. So she creates a 4.5-m-long, 2.0-mm-diameter wire of the material, connects it to a 1.5 V battery, and measures a 3.0 mT magnetic field 1.0 mm from the surface of the wire. What is the material's resistivity
Physics
1 answer:
nalin [4]3 years ago
4 0

Answer:

3.49\times 10^{-8}\ \Omega\text{m}

Explanation:

r = Radius = \dfrac{2}{2}=1\ \text{mm}

B = Magnetic field = 3 mT

1 mm = Distance from the surface of the wire

V = Voltage

x = Distance from the probe = r+1=1+1=2\ \text{mm}

R = Resistance

L = Length of wire = 4.5 m

Magnetic field is given by

B=\dfrac{\mu_0I}{2\pi x}\\\Rightarrow I=\dfrac{B2\pi x}{\mu_0}\\\Rightarrow I=\dfrac{3\times 10^{-3}\times 2\times \pi 2\times 10^{-3}}{4\pi 10^{-7}}\\\Rightarrow I=30\ \text{A}

Voltage is given by

V=IR\\\Rightarrow R=\dfrac{V}{I}\\\Rightarrow R=\dfrac{1.5}{30}\\\Rightarrow R=0.05\ \Omega

Resistivity is given by

\rho=\dfrac{RA}{L}\\\Rightarrow \rho=\dfrac{0.05\times \pi (1\times 10^{-3})^2}{4.5}\\\Rightarrow \rho=3.49\times 10^{-8}\ \Omega\text{m}

The resistivity of the material is 3.49\times 10^{-8}\ \Omega\text{m}.

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Given the data in the question;

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