A girl whirls a stone in a horizontal circle 1.50 m above the ground by means of a string 165 cm long. The string breaks, and th
e stone flies of horizontally and strike the ground 6.90 m away. What is the centripetal acceleration of the stone while in circular motion
1 answer:
Answer:
95.5ms-2
Explanation:
First we obtain the time taken for the motion from the equation of motion. Secondly we obtain the horizontal velocity of the stone. This can now be used to calculate the centripetal acceleration. Note that the length of the chord is the radius of the circle around which the stone moves.
All details are contained in the detailed step-by-step solution attached to this answer.
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Answer:
Therefore the amplitude of the resultant wave is
Explanation:
The equation of wave:
y=A sin (kx-ωt)
For wave 1:
y₁=A sin (kx-ωt) = sin (kx-ωt)
For wave 2:
y₂=A sin (kx-ωt+Φ) = sin (kx-ωt+Φ)
Where A= amplitude=
The angular frequency
,
= wave length.
t= time
T= Time period
= phase difference =
The resultant wave will be
y = y₁ + y₂
= sin (kx-ωt) +
sin (kx-ωt+Φ)
{sin (kx-ωt) + sin (kx-ωt+Φ)}
Therefore the amplitude of the resultant wave is