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3 years ago

Which statement can be supported by using a position-time grap

Physics

1 answer:

Phoenix [80]3 years ago

6 0

Answer:

A negative slope results when an individual is moving away

Explanation:

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Could I get help on this question please

bezimeni [28]

Answer:

I can't see it good on my phone sorry can't help you

8 0

3 years ago

What is the total distance between the diving board and the diver's stopping point underwater?

Artyom0805 [142]

57.0 kg is the answer

5 0

3 years ago

A mass attached to a spring oscillates with a period of 22 sec. After 22 kg are added, the period becomes 33 sec. Assuming that

polet [3.4K]

Answer:

Mass of 17.854 kg is only attached to the spring

Explanation:

We have given time period in first case is 22 sec

Let initially mass is m

After 22 kg are added the period becomes 33 sec

Time period of spring mass system is

$T=2\pi \sqrt{\frac{m}{k}}$ , here m is mass and k is spring constant

From the relation we can see that

$\frac{T_1}{T_2}=\sqrt{\frac{m}{m+22}}$

$\frac{22}{33}=\sqrt{\frac{m}{m+22}}$

Squaring both side

$0.444={\frac{m}{m+22}}$

$0.444m+9.777=m$

m = 17.584 kg

So mass of 17.854 kg is only attached to the spring

7 0

3 years ago

A spring-mounted chair in which the astronaut sits, can be used to find the mass of an astronaut. The chair is then made to osci

emmainna [20.7K]

Answer:

M = 175 kg

Explanation:

In the resolution of the harmonic oscillator movement of a system and a mass with a spring, the angular velocity is

w = √ k / m

Where k is the spring constant and m the mass

In this case the mass is the mass of the chair (m) plus the mass of the astronaut (M)

M all = m + M

The angular velocity and the period are related by

w = 2π / T

Substituting

2π / T = √(k/(m + M))

We calculate the astronaut's mass

4π² / T² = k / (m + M)

M = k T² / 4π² - m

M = 569 3.6² /(4π²) - 11

M = 186.8 - 11

M = 175 kg

4 0

4 years ago

A cart starting from rest rolls down a frictionless 1.0 m high hill. It travels a distance 2.0 m along the rough bottom surface

Rzqust [24]

Answer:

Option B is correct.

Explanation:

Given data

Height of the hill = AB = 1 m

Distance traveled along the rough bottom surface = AC = 2 m

Now from the ΔABC

$\sin \theta = \frac{AB}{AC}$

$\sin \theta = \frac{1}{2}$

$\theta = 30$ °

We know that the coefficient of kinetic friction is

$\mu = \tan \theta$

$\mu = \tan 30$

$\mu =$ 0.5

This is the value of the coefficient of kinetic friction

Thus option B is correct.

8 0

3 years ago