Answer:
(a) 
(b) 142
(c) 
(d) 96.8 mph
(e) 0.426 s
(f) 0.061 rad
Explanation:
Velocity is a time-derivative of position.
(a) 
(b) Since is independent of 
, it follows it was constant throughout. Hence, at any point or time, the horizontal velocity is 142.
(c) 
(d) When it passes the home plate, the ball has travelled 60.5 ft (from the question). This is horizontal, so it is equivalent to 
.
.
In this time, the vertical velocity, 
is
The speed of the ball at thus point is 
ft/s
To convert this to mph, we multiply the factor 3600/5280
(e) The time has been determined from (d) above.
(f) This angle is given by
(Note here we are considering the acute angle so we ignore the negative sign)
In radians, this is
Answer:
The temperature of the core raises by 
every second.
Explanation:
Since the average specific heat of the reactor core is 0.3349 kJ/kgC
It means that we require 0.3349 kJ of heat to raise the temperature of 1 kg of core material by 1 degree Celsius
Thus reactor core whose mass is 
will require
energy to raise it's temperature by 1 degree Celsius in 1 second
Hence by the concept of proportionately we can infer 150 MW of power will increase the temperature by
Ohm’s law states:
I*R = U
So we just fill in:
U = 11 A * 60 Ω = 660 V
Answer:
4 m/s
Explanation:
From the question given above, the following data were obtained:
Maximum range (Rₘₐₓ) = 1.6 m
Acceleration due to gravity (g) = 10 m/s²
Initial velocity (u) =?
The initial velocity of the projectile can be obtained as follow:
Rₘₐₓ = u² / g
1.6 = u² / 10
Cross multiply
u² = 1.6 × 10
u² = 16
Take the square root of both side
u = √16
u = 4 m/s
Therefore, the velocity of the projectile is 4 m/s
