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3 years ago

Find out the reasons why hydrogen is not used as a fuel although it has very high calorific value.

Chemistry

1 answer:

AnnyKZ [126]3 years ago

3 0

Answer:

Although hydrogen has the highest calorific value, it is not used as a domestic fuel. It is because hydrogen is a highly combustible and it reacts explosively when it comes in contact with air. And hence as a result, storing of the hydrogen gas is difficult and is dangerous at the same time.

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A common function of proteins and carbohydrates in the plasma membrane is...

Vika [28.1K]

I believe your answer is B.

8 0

4 years ago

Which of the following coefficients is needed to balance the combustion reaction of methane? a.3 b.2 c.4 d.equation is already b

Alla [95]

I might go with d it seems right to me hope this helps.

3 0

3 years ago

You want to make 500 ml of a 1 N solution of sulfuric acid (H2SO4, MW: 98.1). How many grams of sulfuric acid do you need?

umka21 [38]

Answer:

24.525 g of sulfuric acid.

Explanation:

Hello,

Normality (units of eq/L) is defined as:

$N=\frac{eq_{solute}}{V_{solution}}$

Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:

$eq_{solute}=N*V_{solution}=1\frac{eq}{L}*0.5L=0.5 eq$

Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:

$m_{H_2SO_4}=0.5eqH_2SO_4(\frac{1molH_2SO_4}{2 eqH_2SO_4}) (\frac{98.1 g H_2SO_4}{1 mol H_2SO_4} )\\m_{H_2SO_4}=24.525 g H_2SO_4$

Best regards.

4 0

3 years ago

4. Using your knowledge of elements, compounds

igor_vitrenko [27]

Answer:

Element

magnesium, hydrogen, chlorine, sulfur

Compound

water, iron oxide

Mixture

air, salty water , dias cola.

Explanation:

Element is made up of only one type of atom and are relresented by symbols.

Compound are formed by chemical mixing of atoms of elements and have a chemical formula

Mixture are formed by simple mixing up of substances and mixture don't have chemical formula.

4 0

3 years ago

How much CaCO3 would have to be decomposed to produce 247 g of CaO

vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41$

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

$\tt \dfrac{1}{1}\times 4.41=4.41$

mass CaCO₃(MW=100 g/mol) :

$\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g$

6 0

3 years ago