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Artemon [7]
3 years ago
7

How many orbitals are in the subshell with the following quantum numbers: n=4,l=2,ml=−2,−1,0,1,2?

Chemistry
1 answer:
Rainbow [258]3 years ago
3 0
The answer is the C.5
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What is the value of quantum numbers (n, l, ml, ms) of 2p^3?​
eduard

Answer:

Explanation:

First digit of the 2p^3  gives you value of n,  in this case its = 2, So, n= 2

Second alphabet gives you the value of l,

l=0 =s

l=1 =p

l=3=d

l=4=f

since  "p" is the alphabet  in 2p^3, so in your case lt shoudlbe = 1 right?

ml= -l to +l , that is -1, 0, +1

Ms= +1/2  or -1/2 alaways remains same foe evrything.

6 0
3 years ago
The label on a bottle of medicine reads​ "Each 5 mL teaspoonful contains​ glucose, 1.87​ g; levulose, 1.87​ g; and phosphoric​ a
Alexandra [31]

(a) 43.6 mg; (b) 520 mg

(a) <em>Mass of phosphoric acid (PA) in a dose </em>

Mass of PA = 2 tsp × (21.8 mg PA/1 tsp) = 43.6 mg PA

(b) <em>Mass of PA in the bottle </em>

<em>Step 1</em>. Convert <em>ounces to millilitres </em>

Volume = 4 oz × (30 mL/1 oz) = 120 mL

<em>Step 2.</em> Calculate the mass of PA

Mass of PA = 120 mL × (21.8 mg PA/5 mL) ≈ 520 mg PA

4 0
3 years ago
What pressure (in atm) will 0.44 moles of co2 exert in a 2.6 l container at 25°c?
Lilit [14]
We can use the ideal gas law equation to find the pressure 
PV = nRTwhere 
P - pressure 
V - volume  - 2.6 x 10⁻³ m³ 
n - number of moles - 0.44 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values into the equation,
P x 2.6 x 10⁻³ m³  = 0.44 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 419 281.41 Pa
101 325 Pa is equivalent to 1 atm 
Therefore 419 281.41 Pa - 1/ 101 325 x 419 281.41 = 4.13 atm
Pressure is 4.13 atm
6 0
3 years ago
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