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umka21 [38]
2 years ago
5

At a constant temperature, a sample of helium at 760 torr in a closed container was compressed from 5.0 L to 3.0 L. What was the

new pressure exerted by the helium on its container?
Chemistry
1 answer:
borishaifa [10]2 years ago
7 0

Answer:

The new pressure exerted by the He, is 1266.6 Torr

Explanation:

A typical problem of gases where the volume is increased and the moles and T° keeps on constant. This is an indirect proportion because when the volume of the flask is increased, pressue decreases because molecules  collide to a lesser extent with the walls of the vessel.

P₁ . V₁ = P₂ . V₂

760 Torr . 5L = P₂ . 3L

P₂ = (760 Torr . 5L) / 3L

P₂ = 1266.6 Torr

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3 years ago
Menthol, which is present in mentholated cough drops, is an organic compound
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Answer:

The empirical formula is C10H20O

Explanation:

Step 1: Data given

Mass of the sample = 0.2010 grams

Mass of CO2 = 0.5658 grams

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Moles H2O =0.2318 grams / 18.02 g/mol

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Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

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Step 7: Calculate mass H

Mass H = 0.02572 moles * 1.01 g/mol

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Step8: Calculate mass O

Mass O = 0.2010 - 0.1544 - 0.0260

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Step 9: Calculate moles O

Moles O = 0.0206 grams / 16.0 g/mol

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Step 10: Calculate the mol ratio

We divide by the smallest amount of moles

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H: 0.02572 moles / 0.00129 moles = 20

O: 0.00129 moles / 0.00129 moles = 1

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Explanation:

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