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Pepsi [2]
3 years ago
15

Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and an aque

ous solution of magnesium (II) chloride. What substance is being oxidized. A)H2(g) B)MgCl2(aq) C)HCl(aq) D)Mg(s)
Chemistry
1 answer:
bonufazy [111]3 years ago
3 0

Answer: Mg is being oxidized.

Explanation:

The chemical equation for magnesium metal reacts with hydrochloric acid to produce hydrogen gas and an aqueous solution of magnesium (II) chloride.

Mg(s)+2HCl\rightarrow MgCl_2(aq)+H_2(g)

Oxidation reaction : When there is a loss of electrons and an increase in oxidation state number.

Mg\rightarrow Mg^{2+}+2e^-

Reduction reaction : when there is gain of electrons and a decrease in oxidation state number.

2H^{+}+2e^-\rightarrow H_2

Thus Mg is being oxidized.

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Answer:

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3 years ago
One mole of which substance contains a total of 6.02 x 1023 atoms? (I need help please.)
Korolek [52]

Answer:

Oxygen

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One mole of atoms of oxygen has a mass of 16 g, as 16 is the atomic weight of oxygen, and contains 6.02 X 1023 atoms of oxygen.

8 0
2 years ago
How many protons, neutrons, and electrons are there in one atom of 'H ?
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8 0
3 years ago
You've made the hypothesis that the less rainfall a cactus plant gets, the taller it will grow, since cactuses like dry conditio
Leviafan [203]

A. the height of the cactus plants

Explanation:

The dependent variable in this experiment designed to test this hypothesis is the height of the cactus plants.

In a hypothesis statement, we can always deduce the dependent and independent variables.

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5 0
3 years ago
a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter
ladessa [460]

Answer:

The concentration of chloride ion is 2.82\times10^{-3}\;mol/L

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the Cl^- content 100 ppm suggests the presence of 100 mg of Cl^- in 1 L of solution.

The molar mass of Cl^- is equal to the molar mass of Cl atom as the mass of the excess electron in Cl^- is negligible as compared to the mass of Cl atom.

So, the molar mass of Cl^- is 35.453 g/mol.

Number of moles = (Mass)/(Molar mass)

Hence, the number of moles (N) of Cl^- present in 100 mg (0.100 g) of Cl^- is calculated as shown below:

N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol

So, there is 2.82\times10^{-3}\;mol of Cl^- present in 1 L of solution.

5 0
3 years ago
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