To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.
Then knowing volume of aluminum and the density of it, we can solve for the mass.
D = m/v
Dv = m
2.7 g/ml • 8 ml = 21.6 grams.
Answer:
The volume will be 0.031 L
Explanation:
Since temperature is constant, Boyle's law is applied in this case.
Boyle's law States that at constant temperature, the volume of a given mass of a gas is inversely proportional to it's pressure.
From this statement it was deduced that P1V1 = P2V2
From the question, P1 = 1atm, V1 = 1.55L, P2 = 50 atm and V2 is to be calculated.
V2 = P1V1/P2
= 1×1.55÷50
=0.031 L